Answer:
T = 11.93 N
Explanation:
Newton's second law to the puck in the circular path
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in radial direccion (N)
m : puck mass (kg)
a : radial acceleration of the puck (m/s²)
Data:
m = 0.085 kg
L = 0.72 m = R : radium of the circular path (m)
θ= one revolution = 2Π rad
t= 0.45 s
Angular speed of the puck
ω = θ/t
ω = 1 rev/0.45 s = (2π/0.45) rad/s
ω = 13.96 rad /s
Radial acceleration or centripetal
a = ω²*R
a = (13.96) ²* (0.72)
a = 140.3 m/s²
Magnitude of the tension in the string (T)
We apply the Formula (1)
∑F = m*a
T = (0.085 kg )* (140.3 m/s² )
T = 11.93 N
Answer:
The ratio (U₁/U₂) = 6
Explanation:
U, the potential energy is given as
U = kqQ/r
k = Coulomb's constant
q = charge we're concerned about
Q = charge of the negative plate of the capacitor
r = distance of q from the negative plate of the capacitor.
For charge q₁
U₁ = kq₁Q/s
U₂ = kq₂Q/2s
But q₂ = q₁/3
U₂ becomes U₂ = kq₁Q/6s
U₁ = kq₁Q/s
U₂ = kq₁Q/6s
(U₁/U₂) = 6
Answer:
the answer the correct is 3
Explanation:
Let's use the relationship between momentum and momentum
I = Δp
I = m
- m v₀
Let's calculate
I = 0.4 5.0 - 0
I = 2.0 N s
By Newton's law of action and reaction the force on the ball is equal to the force that the ball exerts on the foot, therefore the impulse on the foot of equal magnitude, but in the opposite direction
I = 2.0 Ns with 60°
When reviewing the answer the correct is 3
Answer:
Explanation:
Given:
- gravitational field strength of moon at a distance R from its center,

- Distance of the satellite from the center of the moon,

<u>Now as we know that the value of gravity of any heavenly body is at height h is given as:</u>

∴The gravitational field strength will become one-fourth of what it is at the surface of the moon.
Answer:
26.67 m/s
Explanation:
From the law of conservation of linear momentum, the initial sum of momentum equals the final sum.
p=mv where p is momentum, m is the mass of object and v is the speed of the object
Initial momentum
The initial momentum will be that of basketball and volleyball, Since basketball is initially at rest, its initial velocity is zero

Final momentum
