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faust18 [17]
2 years ago
8

When plane waves cross a boundary at a non-zero angle to the boundary, each wavefront experiences a change in ........... and ..

.......... .
Physics
1 answer:
blondinia [14]2 years ago
6 0

Answer:

When plane waves cross a boundary at a non-zero angle to the boundary, each wavefront experiences a change in <u>direction</u> and <u>wavelength</u>

Explanation:

Waves that cross the boundary from one medium to another, that have different densities at an angle to the boundary between the two medium is refracted (bent) in the second medium and experiences a change in direction and speed due to a change in the wavelength of the wave

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Car A rounds a curve of 150‐m radius at a constant speed of 54 km/h. At the instant represented, car B is moving at 81 km/h but
Snezhnost [94]

Answer:

Velocity of Afrom B=21m/s

Acceleration of A from B=1.68m/s°2

Explanation:

Given

Radius r=150m

Velocity of a Va= 54km/hr

Va=54*1000/3600=15m/s

Velocity of b Vb=82km/hr

VB=81*1000/3600=22.5mls

The velocity of Car A as observed from B is VBA

VB= VA+VBA

Resolving the vector into X and Y components

For X component= 15cos60=7.5m/s

Y component=22 5sin60=19.48m/s

VBA= √(X^2+Y^2)

VBA= ✓(7.5^2+19.48^2)=21m/s

For acceleration of A observed from B

A=VA^2/r= 15^2/150=1.5m/s

Resolving into Xcomponent=1.5cos60=0.75m/s

Y component=3cos60=1.5

Acceleration BA=√(0.75^2+1.5^2)

1.68m/s

4 0
2 years ago
Read 2 more answers
Janelle wants to buy some strings of decorative lights for her home. She is trying to decide between two strings of lights that
inysia [295]
If she has a choice and the wiring details are stated on the packaging,
then Janelle should look for lights that are wired in parallel within the
string, and she should avoid lights that are wired in series within the string. 

If a single light in a parallel string fails, then only that one goes out. 
The rest of the lights in the string continue to shimmer and glimmer.

If a single light in a series string fails, then ALL of the lights in that string
go out, and it's a substantial engineering challenge to determine which light
actually failed.
6 0
2 years ago
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A glider is gliding through the air at a height of 416 meters with a speed of 45.2 m/s. The glider dives to a height of 278 mete
Verdich [7]

Answer:

<em>The glider's new speed is 68.90 m/s</em>

Explanation:

<u>Principle Of Conservation Of Mechanical Energy</u>

The mechanical energy of a system is the sum of its kinetic and potential energy. When the only potential energy considered in the system is related to the height of an object, then it's called the gravitational potential energy. The kinetic energy of an object of mass m and speed v is

\displaystyle K=\frac{1}{2}mv^2

The gravitational potential energy when it's at a height h from the zero reference is

U=mgh

The total mechanical energy is

M=K+U

\displaystyle M=\frac{1}{2}mv^2+mgh

The principle of conservation of mechanical energy states the total energy is constant while no external force is applied to the system. One example of a non-conservative system happens when friction is considered since part of the energy is lost in its thermal manifestation.

The initial conditions of the problem state that our glider is glides at 416 meters with a speed of 45.2 m/s. The initial mechanical energy is

\displaystyle M_1=\frac{1}{2}m(45.2)v_o^2+m(9.8)(416)

Operating in terms of m

\displaystyle M_1=1021.52m+4076.8m

\displaystyle M_1=5098.32m

Then we know the glider dives to 278 meters and we need to know their final speed, let's call it v_f. The final mechanical energy is

\displaystyle M_2=\frac{1}{2}mv_f^2+m(9.8)(278)

Operating and factoring

\displaystyle M_2=m(\frac{1}{2}v_f^2+2724.4)

Both mechanical energies must be the same, so

\displaystyle m(\frac{1}{2}v_f^2+2724.4)=5098.32m

Simplifying by m and rearranging

\displaystyle \frac{v_f^2}{2}=5098.32-2724.4

Computing

v_f=\sqrt{4747.84}=68.90\ m/s

The glider's new speed is 68.90 m/s

8 0
2 years ago
A metal spoon becomes hot after being left in a pan of boiling water. this is an example of _____. conduction reflection radiati
IRISSAK [1]
Two methods of transfer of heat are involved in this process: conduction and convection.

In fact, the metal spoon is heated by conduction because the molecules of the boiling water collide with the molecules of the spoon, releasing heat to it; and also by convection, because in the pot of boiling water masses of hot water goes upward and they give their heat to the spoon, then these masses become cooler and they go down, replaced by other masses of hot water.
6 0
2 years ago
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The first-order rearrangement of CH3NC is measured to have a rate constant of 3.61 × 10–15 s–1 at 298 K and a rate constant of 8
netineya [11]

Answer:

The activation energy for this reaction, Ea = 159.98 kJ/mol

Explanation:

Using the Arrhenius equation as:

ln\frac {K_2}{K_1}=-\frac {E_a}{R}\times (\frac {1}{T_2}-\frac {1}{T_1})

Where, Ea is the activation energy.

R is the gas constant having value 8.314 J/K.mol

K₂ and K₁ are the rate constants

T₂ and T₁ are the temperature values in kelvin.

Given:

K₂ = 8.66×10⁻⁷ s⁻¹ , T₂ = 425 K

K₁ = 3.61×10⁻¹⁵ s⁻¹ , T₁ = 298 K

Applying in the equation as:

ln\frac {8.66\times 10^{-7}}{3.61\times 10^{-15}}=-\frac {E_a}{8.314}\times (\frac {1}{425}-\frac {1}{298})

Solving for Ea as:

Ea = 159982.23 J /mol

1 J/mol = 10⁻³ kJ/mol

Ea = 159.98 kJ/mol

7 0
2 years ago
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