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gtnhenbr [62]
2 years ago
12

What volume does .0685 mol of gas occupy at STP? 1mole =22.4

Chemistry
2 answers:
SashulF [63]2 years ago
6 0

Answer : The volume of gas at STP is, 1.53 liter

Solution : Given,

Moles of a gas = 0.0685 mole

As we know that at STP,

1 mole of gas contains 22.4 liter volume of gas

As, 1 mole of gas contains 22.4 liter volume of gas

So, 0.0685 mole of gas contains 0.0685\times 22.4=1.53L volume of gas

Therefore, the volume of gas at STP is, 1.53 liter

GuDViN [60]2 years ago
4 0
V = nRT/P
V = 0.685 mol*(.0821 L*atm/K*mol)*273 K/1 atm
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2 years ago
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What is the hydronium ion concentration of a solution whose pH is 7.30
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[ H₃O⁺] = 10 ^ - pH

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[ H₃O⁺ ] = 5.011 x 10⁻⁸ M

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2 years ago
A new student is planning to use thin layer chromatography (TLC) for his research project. After setting up the apparatus the st
tamaranim1 [39]

Answer:

The open system evaporates the solvent in the solution

Explanation:

An open system is a system in which exchange of materials and energy can occur. If a TLC set up is left open, then the set up constitutes an open system.

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Most of these solvents used used TLC are volatile organic compounds. Therefore, if the TLC set up is left open, the solvent will evaporate leading to poor results after running the TLC experiment.

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2 years ago
Iron (Fe) undergoes an allotropic transformation at 912°C: upon heating from a BCC (α phase) to an FCC (γ phase). Accompanying t
-Dominant- [34]

Answer:

The description including its given problem is outlined in the following section on the clarification.

Explanation:

The given values are:

RBCC = 0.12584 nm

RFCC = 0.12894 nm

The unit cell edge length (ABCC) as well as the atomic radius (RBcc) respectively connected as measures for BCC (α-phase) structure:

√3 ABCC = 4RBCC

⇒  ABCC = \frac{4RBCC}{\sqrt{3} }

⇒             = \frac{4\times 0.12584}{\sqrt{3}}

⇒             = 0.29062 \ nm

Likewise AFCC as well as RFCC are interconnected by  

√2AFCC = 4RFCC

⇒  AFCC = \frac{4RFCC}{\sqrt{2}}

⇒             = \frac{4\times 0.12894}{\sqrt{2} }

⇒             = 0.36470 \ nm

Now,

The Change in Percent Volume,

= \frac{V \ final-V \ initial}{V \ initial}\times 100 \ percent

= \frac{(VFCC)unit \ cell-(VBCC)unit \ cell}{(VBCC)unit \ cell}\times 100 \ percent

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= 97.62 \ percent (approximately)

Note: percent = %

7 0
2 years ago
. Divide 94.20 g by 3.167 22 mL.
jeka94
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The ratio of mass to volume is equal to the substance's density. Thus, 29.74 g/mL is the density of whatever substance it may be. Density does not change for incompressible matter like solid and some liquids. Although, it may be temperature dependent.
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