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8090 [49]
2 years ago
13

3. You are walking in Paris alongside the Eiffel Tower and suddenly a croissant smacks you on the head and knocks you to the gro

und. From your handy dandy tourist guidebook you find that the height of the Eiffel Tower is 300.5 m. If you neglect air resistance, calculate how many seconds the croissant dropped before it tagged you on the head.
Physics
1 answer:
Elza [17]2 years ago
5 0

As absurd as the concept is, we must assume that a croissant
can fall 300.5 meters through the moisture-laden, perfumed and
polluted Parisian air with no air resistance whatsoever.

Acceleration due to gravity on Earth:  9.8 m/s²

Distance in clean,
unimpeded free-fall         = (1/2) (acceleration) x (time²) 

                                            300.5 m  =  (1/2)  (9.8 m/s²) (T²)
Divide each side
by (4.9 m/s²):                  (300.5 m) / (4.9 m/s²)  =  T²

Take the square root
of each side:                     T = √(300.5/4.9) (s²)

                                                               =  7.831 seconds .

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They have different accelerations because of their masses. According to Newton's Second Law, an objects acceleration is inversely proportional to its mass. Therefore the object with the larger mass, in this case the gun, will have a smaller acceleration. In the same way, the less massive object, being the bullet, will have a higher acceleration.

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4 0
2 years ago
An object at rest is suddenly broken apart into two fragments by an explosion one fragment acquires twice the kinetic energy of
satela [25.4K]
<span>First, we use the kinetic energy equation to create a formula: Ka = 2Kb 1/2(ma*Va^2) = 2(1/2(mb*Vb^2)) The 1/2 of the right gets cancelled by the 2 left of the bracket so: 1/2(ma*Va^2) = mb*Vb^2 (1) By the definiton of momentum we can say: ma*Va = mb*Vb And with some algebra: Vb = (ma*Va)/mb (2) Substituting (2) into (1), we have: 1/2(ma*Va^2) = mb*((ma*Va)/mb)^2 Then: 1/2(ma*Va^2) = mb*(ma^2*Va^2)/mb^2 We cancel the Va^2 in both sides and cancel the mb at the numerator, leving the denominator of the right side with exponent 1: 1/2(ma) = (ma^2)/mb Cancel the ma of the left, leaving the right one with exponent 1: 1/2 = ma/mb And finally we have that: mb/2 = ma mb = 2ma</span>
8 0
2 years ago
Paintball guns were originally developed to mark trees for logging. A forester aims his gun directly at a knothole in a tree tha
emmasim [6.3K]

Answer:

The distance between knothole and the paint ball is 0.483 m.

Explanation:

Given that,

Height = 4.0 m

Distance = 15 m

Speed = 50 m/s

The angle at which the forester aims his gun are,

\tan\theta=\dfrac{4}{15}

\tan\theta=0.266

\cos\theta=\dfrac{15}{\sqrt{15^2+4^2}}

\cos\theta=0.966

Using the equation of motion of the trajectory

The horizontal displacement of the paint ball is

x=(u\cos\theta)t

t=\dfrac{x}{u\cos\theta}

Using the equation of motion of the trajectory

The vertical displacement of the paint ball is

y=u\sin\theta(t)-\dfrac{1}{2}gt^2

y=u\sin\theta(\dfrac{x}{u\cos\theta})-\dfrac{1}{2}g(\dfrac{x}{u\cos\theta})^2

y=x\tan\theta-\dfrac{gx^3}{2u^2(\cos\theta)^2}

Put the value into the formula

y=(15\times0.266)-(\dfrac{9.8\times(15)^2}{2\times(50)^2\times(0.966)^2})

y=3.517\ m

We need to calculate the distance between knothole and the paint ball

d=h-y

d=4-3.517

d=0.483\ m

Hence, The distance between knothole and the paint ball is 0.483 m.

8 0
2 years ago
Someone fires a 0.04 kg bullet at a block of wood that has a mass of 0.5 kg. (The block of wood is sitting on a frictionless sur
d1i1m1o1n [39]

Answer:

The speed of bullet and wooden bock coupled together, V = 22.22 m/s

Explanation:

Given that,

Mass of the bullet, m = 0.04 Kg

Mass of the wooden block, M = 0.5 Kg

The initial velocity of the bullet, u = 300 m/s

The initial velocity of the wooden block, U = 0 m/s

The final velocity of the bullet and wooden bock coupled together, V = 0 m/s

According to the conservation of linear momentum, the total momentum of the body after impact is equal to the total momentum before impact.

Therefore,

                              mV + MV = mu + MU

                               V(m+M) = mu

                                 V = mu/(m+M)

Substituting the values in the above equation,

                                V = 0.04 Kg x 300 m/s  / (0.04 Kg+ 0.5 Kg)

                                    = 22.22 m/s

Hence, the speed of bullet and wooden bock coupled together, V = 22.22 m/s

8 0
2 years ago
The human ear canal is, on average, 2.5cm long and aids in hearing by acting like a resonant cavity that is closed on one end an
Troyanec [42]

Answer:

3400 Hz

Explanation:

We know that

1 cm = 0.01 m

L = Length of the human ear canal = 2.5 cm = 0.025 m

V = Speed of sound = 340 ms⁻¹

f = First resonant frequency

The human ear canal behaves as a closed pipe and for a closed pipe, nth resonant frequency is given as

f = \frac{(2n - 1)V}{4L}

for first resonant frequency, we have n = 1

Inserting the values

f = \frac{(2(1) - 1) 340}{4(0.025)}

f = \frac{340}{4(0.025)}

f = 3400 Hz

4 0
2 years ago
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