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Arte-miy333 [17]
2 years ago
11

Which statement correctly describes the phosphate ion, mc031-1.jpg? It is composed of one phosphorus atom and four oxygen atoms

covalently bonded together, and there is a –3 charge distributed over the entire ion. It is composed of one phosphorus atom and four oxygen atoms covalently bonded together, and there is a –3 charge on the phosphorus atom. It is composed of one phosphorus atom and four oxygen atoms ionically bonded together, and there is a –3 charge distributed over the entire ion. It is composed of one phosphorus atom and four oxygen atoms ionically bonded together, and there is a –3 charge on the phosphorus atom.
Chemistry
2 answers:
STatiana [176]2 years ago
5 0
The phosphate ion has a formula of PO₄⁻³
It is visible that there is one phosphorus atom and four oxygen atoms. Moreover, we know that both phosphorus and oxygen are non-metallic elements, so the bonding that must be present between them is covalent bonding.
Finally, the charge of an ion is distributed over the entire ion so that it is stabilized. Thus, the answer is:
<span>It is composed of one phosphorus atom and four oxygen atoms covalently bonded together, and there is a –3 charge distributed over the entire ion</span>
trapecia [35]2 years ago
5 0

Answer:

A

Explanation:

Just tested

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In the citric acid cycle, after the acetyl-group (2C) from acetyl-CoA is transferred to oxaloacetate (4C) to produce citrate (6C
Alborosie

Answer:

The carbons of the acetyl group oxidize which generate CO2, and in turn H2O.

Explanation:

The pyruvic acid that is generated during glycolysis enters the mitochondria. Inside this organelle, the acid molecules undergo a process called oxidative decaborxylation in which an enzyme of several cofactors is involved, one of which is coenzyme A. Pyruvic acid is transformed into an acetyl molecule and these are been introduced to the begining of the Krebs Cycle where the acetyl-group (2C) from acetyl-CoA is transferred to oxaloacetate (4C) to produce citrate (6C). As the molecule cycles the two carbons of the acetyl oxidize and are released in the form of CO2. Then the energy of the Krebs cycle becomes sufficient to reduce three NAD +, which means that three NADH molecules are formed. Although a small portion of energy is used to generate ATP, most of it is used to reduce not only the NAD + but also the FAD which, if oxidized, passes to its reduced state, FADH2

8 0
2 years ago
A sample of 0.6760 g of an unknown compound containing barium ions (ba2+) is dissolved in water and treated with an excess of na
notka56 [123]

Answer: 35.72 % of Barium ions will be present in the original unknown compound.

Explanation: The reaction of Barium ions and sodium sulfate is:

Na_2SO_4(aq.)+Ba^{2+}(aq.)\rightarrow BaSO_4(s)+2Na^+(aq.)

Here, Sodium sulfate is present in excess, Barium ions are the limiting reagent because it limits the formation of product.

Now, 1 mole of barium sulfate is produced by 1 mole of Barium ions.

Molar mass of Barium sulfate = 233.38 g/mol

Molar mass of Barium ions = 137.327 g/mol

233.38 g/mol of barium sulfate will be produced by 137.323 g/mol of Barium ions, so

0.4105 grams of barium sulfate will be produced by = \frac{137.327g/mol}{233.38g/mol}\times 0.4105g of Barium ions

Mass of barium ions = 0.2415 grams

To calculate percentage by mass, we use the formula:

\% mass=\frac{\text{Mass of solute (in grams)}}{\text{Total mass of the solution(in grams)}}\times 100

Mass of the solution = 0.6760 grams

Putting the value in above equation, we get

\% \text{ mass of }Ba^{2+}\text{ ions}=\frac{0.2415g}{0.6760g}\times 100

% mass of Barium ions = 35.72%.

8 0
2 years ago
Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.
Tema [17]

Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.

Answer 1) σ Bond a: C sp^{2}  O sp^{2} .

Explanation : The sigma bonds in the 'a' position involves carbon atom which undergoes sp^{2} hybridisation and has sp^{2} orbitals of carbon and as well as oxygen atoms involved in the bonding.

Answer 2) π Bond a: C has π orbitals and  O also has π  orbitals.

Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.

Answer 3) Bond b: O sp^{3}  H has only S orbital involved in bonding.

Explanation : The bonding at 'b' position involves oxygen and hydrogen atoms in it. It has sp^{3} hybridized orbitals and S orbital of hydrogen involved in the bonding.

Answer 4) Bond c:   C sp^{3} O sp^{3}

Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of sp^{3} hybridized bonds.

Answer 5) Bond d:   C sp^{3}  C sp^{3}

Explanation : The bonding involved at the position of 'd' involves two carbon atoms. Therefore, they undergo sp^{3} hybridization. The orbitals involved in this hybridization are also sp^{3}.

Answer 6) Bond e:  C1 containing O sp^{2}    C2 sp^{3}

Explanation : The bonding at the 'e' position involves two carbon atoms on is containing oxygen with double bonds and the C2 carbon atom. The carbon containing oxygen has sp^{2} hybridized orbitals involved in the bonding; whereas C2 carbon ha sp^{3} orbitals.

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7 0
2 years ago
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maria [59]
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<span>RE: "numerically to the hundredths place." </span>

<span>Since, in this case, you're dealing with money, "the hundredths place" simply means, "to the nearest cent."</span>
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2 years ago
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