in order to prepare a 0.523 m aqueous solution of potassium iodide, how many grams of potassium iodide must be added to 2.00 kg
1 answer:
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Explanation:
The given data is as follows.
Moles of propylene = 100 moles, = 300 K
= 800 K,
,
of propylene = 100 J/mol
Now, we assume the following assumptions:
Since, it is a compression process therefore, work will be done on the system. And, work done will be equal to the heat energy liberating without any friction.
W =
=
= 5 MJ
Thus, we can conclude that a minimum of 5 MJ work is required without any friction.
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Explanation:
1. In the first column
<u>INCREASE CONCENTRATION</u>: these are the items that needs to be placed in this bin
a. Add drink mix solid to a diluted mixture of drink mix in pure water
b. Add drink mix solution to a diluted mixture of drink mix in pure water
c. Add drink mix solid to pure drink mix solution
d Evaporate water from a diluted mixture of drink mix in pure water
e Evaporate water from pure drink mix solution
2. The items below are what should be placed in this bin,<u>DECREASE CONCENTRATION:</u>
a. Add water to a diluted mixture of drink mix in pure water
b. Add water to pure drink mix solution
3. These items here should be placed here. <u>DOES NOT AFFECT CONCENTRATION:</u>
a. Add pure drink mix solution to pure drink mix solution
b. Drain the pure drink mix solution
c. Drain the diluted mixture
