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2 years ago

A compressed spring in a toy is used to launch

1 answer:

7 0

Kinetic energy = (1/2) (mass) x (speed²)

If the ball was launched in the horizontal direction,
then its total kinetic energy was

   (1/2) x (0.005 kg) x (5 m/s)²

   = (0.0025 x 25) (kg-m²/sec²)

   =   0.0625 Joule .

And that would be the amount of energy stored in the spring.

If the ball was launched at some angle above the horizontal, then
it had some vertical speed too. Its total kinetic energy was then
some greater number, and there was more energy stored in
the spring.

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A box of mass 8 kg slides across a frictionless surface at an initial speed 1.5 m/s into a relaxed spring of spring constant 69

Sav [38]

Answer:

1.1 sec

Explanation:

m = mass of the box = 8 kg

k = spring constant of the spring = 69 N/m

v = initial speed of the box = 1.5 m/s

t = time period of oscillation of box in contact with the spring

Time period is given as

$t = \pi \sqrt{\frac{m}{k}}$

Inserting the values

$t = (3.14) \sqrt{\frac{8}{69}}$

t = 1.1 sec

5 0

2 years ago

In which landscape region of new york is the most resistant bedrock found?

Nutka1998 [239]

<span>The Adirondack Mountains, Taconic Mountains, and the Hudson Highlands have the most resistant bedrock.</span>

7 0

2 years ago

Read 2 more answers

The resistivity of a silver wire with a radius of 5.04 × 10–4 m is 1.59 × 10–8 ω · m. if the length of the wire is 3.00 m, what

Alexxx [7]

<span>5.98 x 10^-2 ohms. Resistance is defined as: R = rl/A where R = resistance in ohms r = resistivity (given as 1.59x10^-8) l = length of wire. A = Cross sectional area of wire. So plugging into the formula, the known values, including the area of a circle being pi*r^2, gives: R = 1.59x10^-8 * 3.00 / (pi * (5.04 x 10^-4)^2) R = (4.77 x 10^-8) / (pi * 2.54016 x 10 ^-7) R = (4.77 x 10^-8) / (7.98015 x 10^-7) R = 5.98 x 10^-2 ohms So that wire has a resistance of 5.98 x 10^-2 ohms.</span>

4 0

2 years ago

How far could a rabbit run if it ran 36km/h for 5.0min?

Korolek [52]

3 kilometers, it is just 5/60 or 1/12 multiplied by 36.

4 0

2 years ago

Read 2 more answers

A diver in the pike position (legs straight, hands on ankles) usually makes only one or one-and-a-half rotations. To make two or

Korolek [52]

Answer:

from the above analysis we can say that the angular velocity in the later case is more than that of the former case. This means that the number of rotation made in the truck case is more than that made in pike position.

Explanation:

This can be explained on the basis of conservation of angular momentum.

This means the initial and the final angular velocity is conserved. Consider initial position (1)in the pike and final position in the be truck position. So there inertia's will also be different.

⇒ $I_1\omega_1 = I_2\omega_2$

$\frac{I_1}{I_2} = \frac{\omega_2}{\omega_1}$

also,

$I_1= mr_1^2$

$I_2= mr_2^2$

since, $r_2^2$

$I_2^2$

therefore,

$\omega_1^2$

So, from the above analysis we can say that the angular velocity in the later case is more than that of the former case. This means that the number of rotation made in the truck case is more than that made in pike position.

6 0

2 years ago