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zalisa [80]
2 years ago
15

s the work shown below correct? Explain your answer. (11 + 2i ) – (3 – 10i ) = 11 + 2i – 3 – 10i = (11 – 3) + (2i – 10i) = 8 – 8

i
Mathematics
2 answers:
Anna007 [38]2 years ago
6 0

Answer:

Given that: (11+2i)-(3-10i)

Remove the parentheses, we have;

11+2i-3+10i

Like terms are those terms which have same variables to the same power.

Combine like terms of a constant variable;

(11-3) +2i+10i

Similarly, combine like terms of imaginary part, we have;

(11-3) +(2i+10i)

Simplify:

8 +(12i)

or

8+12i

Therefore, the correct solution of (11+2i)-(3-10i) = 8+12i

jok3333 [9.3K]2 years ago
5 0
No, because -(3-10i)=-3+10i
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A car rental firm has the following charges for a certain type of car: $25 per day with 100 free miles included, $0.15 per mile
Eddi Din [679]

y = 25 + 0.15x is the equation for relating the cost y to the number of miles x that you drive the car

<em><u>Solution:</u></em>

Let "y" be the total cost of car rental

Let "x" be the number of miles you drive the car for more than 100 miles

<em><u>A car rental firm has the following charges for a certain type of car:</u></em>

$25 per day with 100 free miles included, $0.15 per mile for more than 100 miles

<em><u>Suppose you want to rent a car for one day, and you know you'll use it for more than 100 miles</u></em>

Therefore,

Car is rented for one day

You will use it for more than 100 miles

Therefore, equation is framed as:

Total cost = $ 25 + 0.15(number of hours)

Total\ Cost = 25 + 0.15x\\\\y = 25 + 0.15x

Thus the equation for relating the cost y to the number of miles x that you drive the car

7 0
2 years ago
Each day that a library book is kept past its due date, a $0.30 fee is charged at midnight. Which ordered pair is a viable solut
Murrr4er [49]
Let's say the number of days library book is late is X, and the total fee is Y.

Liability charges $0.30 dollars as a fee for being 1 day late,

For being 1 day late, fee charge is: 1* $0.30
So, for X days the charge would be: X*$0.30.

Total charge for being X days late is Y, Which means: Y= 0.30 * X.

Now We would have to check all the viable solutions in the answer to see if they satisfy the equation Y= 0.30 * X

Option one(-3, -0.9) and two (-2.5, -0.75) Would not be a viable solution because the value of number of days can not be negative and in option one and two, value of days -3 and -2.5 is negative.

Option three(4.5, 1.35) can not be correct because library charges fee for a full day so the number for days would be a whole number. Library would not charge for 4.5 days, they would either charge of 4 days or 5 days because 4.5 is not an whole number.


Option four(8, 2.40) is the correct answer because it satisfies our equation;

Y= 0.30 * X

2.40= 0.30 * 8

2.40 = 2.40.


Fourth option (8, 2.40) is the only viable solution to this question.
5 0
2 years ago
Read 2 more answers
If the probability of winning a carnival game was 2/5 and Max played it five times, write an expression that would calculate the
Dvinal [7]
Prob(winning carnival game) = 2/5 
<span>Prob(losing carnival game) = 3/5 </span>

<span>Prob (Max wins first 3 games, but loses last 2 games) </span>

<span>= Prob(Max wins game 1) * Prob(Max wins game 2) * Prob(Max wins game 3) * Prob(Max loses game 4) * Prob(Max loses game 5) </span>
8 0
2 years ago
Royce has $15 with him and spends $12 to buy his favorite comics. He has $3 left, which he deposits in the bank. Which number wi
Damm [24]
The value 3 will be entered. It's a positive value to indicate he is not in debt of any kind. 
7 0
2 years ago
David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below.
Vikentia [17]

Answer:

Given Polynomial:

80b^4-32b^2c^3+48b^4c

Factors of Coefficient of terms

80 = 5 × 16

32 = 2 × 16

48 = 3 × 16

Common factor of the coefficient of all term is 16.

Each term contain variable. So the Minimum power of b is common from all terms.

Common from all variable part comes b².

So, Common factor of the polynomial = 16b²

⇒ 16b² ( 5b² ) - 16b² ( 2c³ ) + 16b² ( 3b²c )

⇒ 16b² ( 5b² - 2c³ + 3b²c )

Therefore, Statements that are true about David's word are:

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

In step 6, David applied the distributive property

8 0
2 years ago
Read 2 more answers
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