Ask question

Ask question

All categories

1 year ago

8

A 3.5 M KNO3 solution contains 3.5 miles of KNO3 dissolved in A) 1.0 liter of solution B) 1.0 liter of solvent C) 3.5 liters of

solution D) 3.5 liters of solvent

1 answer:

Vladimir [108]1 year ago

4 0

N=3.5 mol
c=3.5 mol/L

n=cv

v=n/c

v=3.5/3.5=1.0 L

A) 1.0 liter of solution

You might be interested in

What term refers to the coldest and densest zone, deep below the surface of a lake?

uranmaximum [27]

Profundal

profundal zone is the coldest and deepest zone

5 0

2 years ago

Read 2 more answers

7. A gas-filled weather balloon with a volume of 65.0 L is released at sea-level conditions of

Galina-37 [17]

The balloon will reach its maximum volume and it will burst.

Given:

A weather balloon at sea level, with gas at 65.0 L volume, 745 Torr pressure, and 25C temperature.
When the balloon was taken to an altitude at which temperature was 25C and pressure was 0.066atm its volume expanded.
The maximum volume of the weather balloon is 835 L.

To find:

Whether the weather balloon will reach its maximum volume or not.

Solution:

The pressure of the gas in the weather balloon at sea level = $P_1=745 torr$

$1 atm = 760 torr\\P_1=745 torr=\frac{745}{760} torr = 0.980 atm$

The volume of the weather balloon at sea level = $V_1=65.0L$

The temperature of the gas in the weather balloon at sea level:

$T_1=25^oC=25+273.15 K=298.15 K$

The balloon rises to an altitude.

The pressure of the gas in the weather balloon at the given altitude:

$P_2=0.066atm$

The volume of the weather balloon at the given altitude = $V_2=?$

The temperature of the gas in the weather balloon at the given altitude:

$T_1=25^oC=25+273.15 K=298.15 K$

Using the Combined gas law:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\\\frac{0.980 atm\times 65.0L}{298.15 K}=\frac{0.066atm\times V_2}{298.15K}\\V_2=\frac{0.980 atm\times 65.0L\times 298.15K}{0.066atm\times 298.15 K}\\=965L$

The maximum volume of the weather balloon= V = 835 L

$V < V_2$

The volume of the weather balloon at a given altitude is greater than its maximum volume which means the balloon will reach its maximum volume and it will burst.

Learn more about the combined gas law:

brainly.com/question/13154969?referrer=searchResults

brainly.com/question/936103?referrer=searchResults

4 0

1 year ago

A buffer is prepared by mixing hypochlorous acid ( HClO ) and sodium hypochlorite ( NaClO ) . If a strong base, such as NaOH , i

Dafna1 [17]

<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

We are given:

A weak acid that is hypochlorous acid (HClO) and basic salt that is sodium hypochlorite (NaClO)

When a strong base is added to the buffer, the hydroxide ion will be neutralized by hydrogen ions from the acid.

So, the buffer component that neutralizes the additional hydroxide ions in the solution is HClO

The chemical equation for the neutralization of hydroxide ion with acid follows:

$HClO+OH^-\rightarrow H_2O+ClO^-$

Hence, the balanced chemical equation is written below.

4 0

2 years ago

What volume, in ml, of a 0.2089 m ki solution contains enough ki to react exactly with the cu(no3)2 in 43.88 ml of a 0.3842 m so

Triss [41]

The reaction is given as: $2Cu(NO_{3})_{2}+4KI\rightarrow 2CuI+I_{2}+4KNO_{3}$ Here, two moles of copper nitrate reacts with four moles of potassium iodide to give two moles of copper iodide, one mole of iodine and four moles of potassium nitrate. First, calculate the number of moles of copper nitrate. Number of moles is equal to the product of molarity and volume of solution in litre. Number of moles = $0.3842 M\times 0.04388 L$ (1 L =1000 mL)

= $0.016858696 mole$

Copper nitrate requires = $0.016858696 \times \frac{4}{2}$ mole of potassium iodide

= $0.033717392 mole$ of potassium iodide

Volume of solution in litre = $\frac{number of moles}{Molarity}$

Thus, volume of potassium iodide is = $\frac{0.033717392}{0.2089}$

= $0.1614 L$

1 L =1000 mL

Volume of potassium iodide in mL = $161.4 mL$

Hence, $161.4 mL$ 0.2089 M potassium iodide consist of sufficient potassium iodide to react with copper nitrate in 3.88 mL of a 0.3842 M solution of copper nitrate .

7 0

1 year ago

Write a net ionic equation to show how piperidine, c5h11n, behaves as a base in water.

lidiya [134]

$C_5H_{11}N + H2O ---\ \textgreater \ C_5H_{11}NH^{+} + OH^{-}$

Nitrogen lone pair will act as a base,removing H+ from water leaving behind OH- ion.
Why ?
Because N is a better donor than O.

7 0

2 years ago