Answer:
string's damping is 1.03676
Explanation:
given data
sound level = 9.0 dB
time = 1 sec
to find out
string's damping
solution
we will apply here formula for string damping (b) that is
A(t) = A × 
...................1
we know here I ∝ A² so
√I(t) = √I ×
√I(t) / √I = .....................2
we know sound level decreases 9 dB i.e ΔdB = 9
so we can write
ΔdB = 10 log ( I(t) / I)
9 = 10 log ( I(t) / I)
I(t) / I = 
I(t) / I = 0.1258
and
√I(t) / I) = √0.1258 = 0.3546 .......................3
from equation 2 and 3 we get
0.3546 =
take ln both side
-bt = ln 0.3546
here we know t is 1 sec
so
- b = - 1.03676
b = 1.03676
so here string's damping is 1.03676
Sorry, I’m only in 6th Grade, I don’t know the answer to this question.
Given Information:
Inclined plane length = 8 m
Inclined plane height = 2 m
Weight of ice block = 300 N
Required Information:
Force required to push ice block = F = ?
Answer:
Force required to push ice block = 75 N
Explanation:
The force required to push this block of ice on a inclined plane is given by
F = Wsinθ
Where W is the weight of the ice block and θ is the angle as shown in the attached image.
Recall from trigonometry ratios,
sinθ = opposite/hypotenuse
Where opposite is height of the inclined plane and hypotenuse in the length of the inclined plane.
sinθ = 2/8
θ = sin⁻¹(2/8)
θ = 14.48°
F = 300*sin(14.48)
F = 75 N
Therefore, a force of 75 N is required to push this ice block on the given inclined plane.
Wavelength can be calculated using the following formula: wavelength = wave velocity/frequency. Wavelength usually is expressed in units of meters.
Answer:
The value is 
Explanation:
Generally the velocity attained by the sled after t = 3.10 s is mathematically evaluated using the kinematic equation as follows
Here u = 0 \ m/s
a = 13.5 
So
=> 
The is distance it covers at this time is
=> 
=> 
Now when sled stops its the final velocity is 
while the initial velocity will be the velocity after its acceleration i.e
So
Here 
, the negative sign shows that it is deceleration
So
=>
