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2 years ago

Which process is a form of mechanical weathering?

2 answers:

8 0

Mechanical weathering is actually breaking down of rocks into smaller pieces by natural forces. Any weathering processes that can cause the physical breakdown of rocks without any type of change in the chemical composition of rocks, called mechanical weathering.

So, looking at each of the definitions in the options, we can easily choose:
1. Hydration : It's a process of absorbing water by substance.

2. Carbonation: It's a process of Carbon Dioxide dissolving in liquid (mostly water).

3. Oxidation : It's a process of oxygen reacting with some element.

4. <span>Exfoliation: It's a process where the rocks erodes by peeling off in sheets or layer by layer rather than grain by grain.

As you can see the last one </span><span>Exfoliation matches with the definition of mechanical weathering. It's one of its types.</span>

Anuta_ua [19.1K]2 years ago

7 0

Answer:

thermal expansion

Explanation:

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A horse and rider are racing to the right with a speed of 21\,\dfrac{\text m}{\text s}21 s m 21, start fraction, start text, m

Marrrta [24]

Answer:

a=-4.2 m/s²

Explanation:

The horse riding so inital velocity is given finally the rider stops so the final velocity is zero.

initial velocity =Vi= 21 m/s

final velocity =Vf= 0 m/s

distance covered = S=52 m

By using 2nd equation of motion we can find the acceleration

2aS=Vf² -Vi²

a=(-441)/104

a=-4.2 m/s²

So the accceleration is 4.2 m/s².

7 0

2 years ago

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What is the threshold frequency for sodium metal if a photon with frequency 6.66 × 1014 s−1 ejects a photon with 7.74 × 10−20 J

FrozenT [24]

Answer:

5.5 × 10^14 Hz or s^-1

no orange light has less frequency so no photoelectric effect

Explanation:

hf = hf0 + K.E

HERE h is Planck 's constant having value 6.63 × 10 ^-34 J s

f is frequency of incident photon and f0 is threshold frequency

hf0 = hf- k.E

6.63 × 10 ^-34 × f0 = 6.63 × 10 ^-34× 6.66 × 10^14 - 7.74× 10^-20

6.63 × 10 ^-34 × f0 = 3.64158×10^-19

f0 = 3.64158×10^-19/ 6.63 × 10 ^-34

f0 = 5.4925 × 10^14

f0 =5.5 × 10^14 Hz or s^-1

frequency of orange light is 4.82 × 10^14 Hz which is less than threshold frequency hence photo electric effect will not be observed for orange light

8 0

2 years ago

Emmy kicks a soccer ball up at an angle of 45° over a level field. She watches the ball's trajectory and notices that it lands,

Elenna [48]

Let $u$ be the initial velocity of the soccer ball at an angle of inclination of $\theta_0$ with the positive x-axis.

Given that:

$\theta_0=45^{\circ}$

The horizontal distance covered by the projectile=20 m

Time of flight, $t_f=2$ seconds

Acceleration due to gravity, $g= 10 m/s^2$ downward.

As "north" and "up" as the positive x ‑ and y ‑directions, respectively.

So, $g= -10 m/s^2$

As the acceleration due to gravity is in the vertical direction, so the horizontal component of the initial velocity remains unchanged.

The x-component of the initial velocity, $u_x=u\cos\theta_0$ .

The horizontal distance covered by the projectile $= u_x\times t_f$

$\Rightarrow u_x\times t_f=20$

$\Rightarrow u_x\times 2=20$

$\Rightarrow u_x=10$ m/s

So, the horizontal component of the velocity is 10 m/s which is constant and the graph has been shown in the figure (i).

Now, $u\cos(45^{\circ})=10$ [as $u_x=u\cos\theta_0$ ]

$\Rightarrow u=10\sqrt{2}$ m/s.

The vertical component of the initial velocity,

$u_y= u\sin\theta_0$

$\Rightarrow u_y=10\sqrt{2}\sin(45^{\circ})$

$\Rightarrow u_y=10$ m/s

Let v be the vertical component of the velocity at any time instant t.

From the equation of motion,

$v=u+at$

where u: initial velocity, v: final velocity, a: constant acceleration, and t: time taken to change the velocity from u to v.

In this case, we have $u=u_y, a= -10 m/s^2$ .

So at any time instant, t.

$v=u_y+(-10)t$

$\Rightarrow v=10-10t$

The vertical component of the velocity, v, is the function of time and related as $v=10-10t$ .

This is a linear equation.

At 2 second, the vertical component of the velocity

v=10-10x2=-10 m/s.

The graph has been shown in figure (ii).

7 0

2 years ago

If the gauge pressure of a gas is 114 kPa, what is the absolute pressure?

Anastasy [175]

Answer:

D. 214 kPa

Explanation:

The absolute pressure is given by:

$p = p_a + p_g$

where

p is the absolute pressure

$p_a \sim 100 kPa$ is the atmospheric pressure

$p_g$ is the gauge pressure

In this problem, we have

$p_g = 114 kPa$

So, the atmospheric pressure is

$p = 100 kPa + 114 kPa = 214 kPa$

4 0

2 years ago

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A zebra runs across a field at a constant speed of 14m/s how far does the zebra go in 8 seconds?

Ratling [72]

Answer:

112m/s

Explanation:

14x8=112 therefore meaning the zebra would run 112m/s

3 0

2 years ago

Read 2 more answers