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Alenkinab [10]
2 years ago
15

Which two vectors, when subtracted (i.e., when one vector is subtracted from the other), will have the largest magnitude?

Physics
1 answer:
FromTheMoon [43]2 years ago
7 0

Given: Please see the attached image below.

 

To be able to subtract vectors, we can either use the parallelogram method or the triangle method. Take note that the only difference is that alternatively adding vectors A and B, we will instead be adding A and – B. When we ponder of vector subtraction, we must anticipate about it in terms of adding a negative vector. A negative vector has the same magnitude as the original vector, however, it has an opposite direction.

 

So in this problem, the two vectors that will have the largest magnitude are A & F when subtracted (i.e., when one vector is subtracted from the other).

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Fiber optic (FO) cables are based upon the concept of total internal reflection (TIR), which is achieved when the FO core and cl
kozerog [31]

Answer:

False

Explanation:

Though fiber active cable is based on the concept of internal reflection but it is achieved by refractive index which transmit data through fast traveling pulses of light. It has a layer of glass and insulating casing called “cladding,”and this is is wrapped around the central fiber thereby causing light to continuously bounce back from the walls of the Cable.

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A graduated cylinder contains 17.5 ml of water. When a metal cube is placed onto the cylinder, its water level rises to 20.3 ml
pogonyaev
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3 0
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If a 110 kg go-cart traveling at a velocity of 13.41 m/s has a collision with an impulse of 615 Nxs, what is the
mafiozo [28]

Answer:

5.59 m/s

Explanation:

We are given;

Mass = 110 kg

Initial velocity: u = 13.41 m/s

Force = 615 N

Time(t) = 1 s

Now, the formula for force is;

Force = mass x acceleration

Thus;

615 = 110 × acceleration

\Acceleration(a) = 615/110 = 5.591 m/s²

Now, using Newton's first law of motion, we can find acceleration (a). Thus;

v = u + at

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So,the change in velocity is;

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6 0
2 years ago
A ship 1200m off shore fires a gun. how long after the gun is fired will it be heard on the shore?​
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Answer:

We know that the speed of sound is 343 m/s in air

we are also given the distance of the boat from the shore

From the provided data, we can easily find the time taken by the sound to reach the shore using the second equation of motion

s = ut + 1/2 at²

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Replacing the variables in the equation with the values we know

1200 = 343 * t

t = 1200 / 343

t = 3.5 seconds (approx)

Therefore, the sound of the gun will be heard at the shore, 3.5 seconds after being fired

6 0
2 years ago
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