Question

How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa)?

Answer 1

Use ideal gas equation:

n = PV / RT

P = 100kPa = 100 x 1000 x (9.8 x 10^{-6}) = 0.98 atm
convert kPa to atm. 1 Pa = 9.8 x 10^{-6} atm
T = 293 K
V = 6.8 L
R = 1/12
put all values.
So, n = 0.272