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madreJ [45]
2 years ago
15

Relative to some reference points,your nose is in motion when you run. relative to others, it is not in motion. give one example

of each
Physics
1 answer:
Fed [463]2 years ago
8 0
When you run, your nose is moving in a straight line relative to a stone on the ground, and it's also moving back and forth relative to your left foot. But it's at rest relative to your ear.
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The muzzle velocity of a 50.0g shell leaving a 3.00 kg rifle is 400m/s what is the recoil velocity of the rifle
serg [7]

Here if we consider bullet and gun as a system then we can say that momentum of the system will remain conserved

so we will have

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

now we know that

m_1 = 50 g = 0.050 kg

m_2 = 3 kg

v_{1i} = v_{2i} = 0

v_{1f} = 400 m/s

now we will have

0.050(0) + 3(0) = 0.050(400) + 3(v)

20 + 3v = 0

v = - \frac{20}{3} = - 6.67 m/s

so gun will recoil with speed 6.67 m/s

6 0
2 years ago
When a 12.0-V battery causes 2.00 μC of charge to flow onto the plates of an air-filled capacitor, how much work did the battery
Mrac [35]

Answer:

Explanation:

Voltage, V = 12 V

Charge, q = 2 micro coulomb = 2 x 10^-6 C

Work = energy

W = 0.5 x q x V

W = 0.5 x 2 x 10^-6 x 12

W = 12 x 10^-6 J

7 0
2 years ago
Read 2 more answers
The system consists of a 20-lb disk A, 4-lb slender rod BC, and a 1-lb smooth collar C. If the disk rolls without slipping, dete
dlinn [17]

Answer:

The velocity of the collar will be 3.076 ft/s

Explanation:

Given data

weight of the disk, Wa = 20lb

weight of rod BC, Wbc = 4lb

weight of collar, Wc = 1lb

Considering the equation of equilibrium

Vb = 1.5Wbc

Wa = 1.875 Wbc

to calculate the velocity of the collar using energy conservation equation

T1 + V1 = T2 + V2

0+4(1.5 \sin 45)+2(3 \sin 45)=\frac{1}{2}\left(\frac{1}{2}\left(\frac{20}{32.2}\right)(0.8)\right)              

=>(1.875 W b c)+\frac{1}{2}\left(\frac{20}{32.2}\right)(1.5 W b c)+\frac{1}{2}\left(\frac{20}{32.2}\right)

=>(1.5 W b c) \frac{1}{2}\left\{\frac{1}{12}\left(\frac{4}{32.2}\right)(3)\right\}+\frac{1}{2}\left(\frac{1}{32.2}\right)

=>(2.598 W b c)+4(1.5 \sin 0)+2(3 \sin 0)

Wbc = 1.18rad/sec

i.e.                                    

V _c=2.598 \times 1.18

= 3.076 ft/ s

5 0
2 years ago
A reel of flexible power cable is mounted on the dolly, which is fixed in position. There are 190 ft of cable weighing 0.402 lb
White raven [17]

Answer:

Explanation:

Total mass of cable m = 190 x .402 = 76.38 lb

moment of inertial due to this cable = m r²

= 76.38 x (14/12)²

= 103.96 lb ft²

moment of inertia of empty spoon

= mR² where R is radius of gyration

= 65 x (11 / 12 )²

= 54.61 lb ft²

Total moment of inertia I = 158.57 lb ft²

Net force applied = force applied - frictional force

= 33 - 15 = 18 lb

= 18 x 32 poundal

= 576 poundal

Torque applied = force x radius

= 576 x 14/12

= 672 unit

Angular acceleration = torque / total moment of inertia

= 672 / 158.57

= 4.238 radian / s²

5 0
2 years ago
If 500 thousand btus of energy are available to raise the temperature of a water boiler from 20°f to 100°f, how many gallons o
sashaice [31]
In this question, you are given the energy( 500,000btus) and the temperature difference( 100F-20F= 80F). You are asked to find the volume of water.
1 BTU mean 1 degree of F increased for 1 pound mass. First, we can calculate the mass of the water in lb unit. The calculation would be:

mass= energy/temperature increase = 500,000/80= 6250lb.

Then we need to convert the weight into gallons. The calculation would be:
6250lb x kg/2.204lb x 1kg/m3 x 264.172 gallons/m3= 3638969.3 gallons
7 0
2 years ago
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