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LiRa [457]
2 years ago
12

A bullet is shot from a rifle with a speed of 720 m/s. What time is required for the bullet to strike a target 3240 meters away

?
Physics
2 answers:
Alik [6]2 years ago
7 0
4.5 seconds you devoured 3240/720=4.5
Nataliya [291]2 years ago
4 0

Answer:

Time taken, t = 4.5 seconds

Explanation:

Speed of the bullet, v = 720 m/s

Distance to be covered by the target, d = 3240 m

Let t is the time required for the bullet to strike a target. The time taken is calculated as :

t=\dfrac{d}{v}

t=\dfrac{3240\ m}{720\ m/s}

t = 4.5 seconds

So, the time required for the bullet to strike a target is 4.5 seconds. Hence, this is the required solution.

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What voltage is required to move 6A through 20?<br><br>​
Marina CMI [18]

Answer:

120V

Explanation:

Given parameters:

Current  = 6A

Resistance  = 20Ω

Unknown:

Voltage = ?

Solution:

According to ohms law;

           V = IR

Where V is the voltage

            I is the current

            R is the resistance

Now, insert the parameters and solve;

    V  = 6 x 20  = 120V

7 0
2 years ago
The blade of metal cutter is shorter than that scissors of tailors<br><br>​
Naily [24]

Explanation:it is beause they are sharper and also have less surface area and therefore more pressure

8 0
2 years ago
You are called as an expert witness to analyze the following auto accident: Car B, of mass 2100 kg, was stopped at a red light w
Artemon [7]

Answer:

Explanation:

Force of friction at car B ( break was applied by car B ) =μ mg = .65 x  2100 X 9.8  = 13377 N .

work done by friction = 13377 x 7.30 = 97652.1 J

If v be the common velocity of both the cars after collision

kinetic energy of both the cars = 1/2 ( 2100 + 1500 ) x v²

= 1800 v²

so , applying work - energy theory ,

1800 v² = 97652.1

v² = 54.25

v = 7.365 m /s

This is the common velocity of both the cars .

To know the speed of car A , we shall apply law of conservation of momentum  .Let the speed of car A before collision be v₁ .

So , momentum before collision = momentum after collision of both the cars

1500 x v₁ = ( 1500 + 2100 ) x 7.365

v₁ = 17.676 m /s

= 63.63 mph .

( b )

yes Car A was crossing speed limit by a difference of

63.63 - 35 = 28.63 mph.

7 0
2 years ago
Two resistors have resistances R1= ( 24+- 0.5)ohm and R2 = (8 +-0.3)ohm . Calculate the absolute error and the percentage relati
zysi [14]

Answer:

Absolute error=0.006

Percentage Relative error=0.6

Explanation:

The resistors have resistance of 24 ohm and 8 ohm.

The change in resistance is 0.5 and 0.3 ohm respectively.

Relative error for parallel combination of resistors is

= dR/R²

= dR1/R1² + dR2/R2²

= 0.5/(24)² + 0.3/(8)²

= 0.5/ 24*24 + 0.3/ 64

= 0.5/576+0.3/ 64

= 32 + 172.8/ 36,864

=204.8/ 36,864=0.0055

=0.006

Percentage error =Relative error *100

= 0.006* 100 = 0.6

8 0
2 years ago
Sketch a position-time graph for a bear starting
Dmitrij [34]

Explanation:

hopefully that makes sense. the position doesn't change over the 5 seconds, meaning it's stopped but time still continues. then when the slope is negative this shows the bear's position becoming negative (backing up, changing direction).

3 0
2 years ago
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