A bullet is shot from a rifle with a speed of 720 m/s. What time is required for the bullet to strike a target 3240 meters away
2 answers:
Answer:
Time taken, t = 4.5 seconds
Explanation:
Speed of the bullet, v = 720 m/s
Distance to be covered by the target, d = 3240 m
Let t is the time required for the bullet to strike a target. The time taken is calculated as :
t = 4.5 seconds
So, the time required for the bullet to strike a target is 4.5 seconds. Hence, this is the required solution.
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Answer:
Explanation:
Given
acceleration of object
(b)For maximum positive displacement velocity must be zero at that instant
i.e.
substitute the value of t
75.17 mg of the radioactive substance will remain after 24 hours.
Answer:
Explanation:
Any radioactive substance will obey the exponential decay behavior. So according to this behavior, any radioactive substance will be decaying in terms of exponential form of disintegration constant and Time.
Disintegration constant is the rate of decay of radioactive elements. It can be measured using the half life time of the radioactive element .While half life time is the time taken by any radioactive element to decay half of its concentration. Like in this case, at first the scientist took 200 mg then after 17 hours, it got reduced to 100 g. So the half life time of this element is 17 hours.
Then Disintegration constant = 0.6932/Half Life time
Disintegration constant = 0.6932/17=0.041
Then as per the law of disintegration constant:
Here N is the amount of radioactive element remaining at time t and is the initial amount of sample, x is the disintegration constant.
So here, = 200 mg, x = 0.041 and t = 24 hrs.
N = 200 × =75.17 mg.
So 75.17 mg of the radioactive substance will remain after 24 hours.