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2 years ago

A ball rolls around a circular track with an angular velocity of 4π rad/s. what is the period of the motion

1 answer:

4 0

The period, T, is the time required for one revolution.

The angular velocity is 4π rad/s.
Because one revolution = 2π radians, the period is
T = (2π rad)/(4π rad/s) = 0.05 s.

Answer: 0.5 s

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un tanque de gasolina de 40 litros fue llenado por la noche, cuando la temperatura era de 68 grados farenheit. Al dia siguiente

Sedaia [141]

Answer:

Volume of gasoline that expands and spills out is 1.33 ltr

Explanation:

As we know that when temperature of the liquid is increased then its volume will expand and it is given as

$\Delta V = V_o\gamma \Delta T$

here we know that

$V_o = 40 Ltr$

volume expansion coefficient of the gasoline is given as

$\gamma = 950 × 10^{–6}$

change in temperature is given as

$\Delta T = (131 - 68) \times \frac{5}{9}$

$\Delta T = 35 ^oC$

Now we have

$\Delta V = 40(950 \times 10^{-6})(35)$

$\Delta V = 1.33 Ltr$

3 0

2 years ago

You hear the engine roaring on a race car at the starting line. Predict the changes in the sound as the race starts and the car

gogolik [260]

B. The sound of the engine will get louder and the pitch higher.

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2 years ago

Read 2 more answers

Two narrow slits spaced 100 microns apart are exposed to light of 600 nm. At what angle does the first minimum (dark space) occu

kumpel [21]

Answer:

The angle is $\theta = 0.1719^o$

Explanation:

From the question we are told that

The distance of separation is $d = 100 * 10^{-6} \ m$

The wavelength of light is $\lambda = 600 nm = 600 *10^{-9} \ m$

Generally the condition for destructive interference is mathematically represented as

$dsin(\theta ) =[m + \frac{1}{2} ]\lambda$

Here m is the order of maxima, first minimum (dark space) m = 0

$100 *10^{-6 } * sin(\theta ) =[0 + \frac{1}{2} ]600 *10^{-9}$

=> $\theta = sin^{-1} [0.003]$

=> $\theta = 0.1719^o$

7 0

2 years ago

A plastic rod is rubbed against a wool shirt, thereby acquiring a charge of −4.9 µc. how many electrons are transferred from the

creativ13 [48]

To find the number of electrons transferred, we should divide the total charge acquired by the rod $Q=-4.9 \mu C=-4.9 \cdot 10^{-6}C$ by the charge of a single electron ( $e=-1.6 \cdot 10^{-19}C$ ), and we find:
$N= \frac{Q}{e}= \frac{-4.9 \cdot 10^{-6}C}{-1.6 \cdot 10^{-19}C} =3.1 \cdot 10^{13}$

5 0

2 years ago

A rock is projected from the edge of the top of a building with an initial velocity of 12.2 m/s at an angle of 53° above the hor

Volgvan

Answer:

h=23.67 m : Building height

Explanation:

The rock describes a parabolic path.

The parabolic movement results from the composition of a uniform rectilinear motion (horizontal ) and a uniformly accelerated rectilinear motion of upward or downward motion (vertical ).

The equation of uniform rectilinear motion (horizontal ) for the x axis is :

x = xi + vx*t Equation (1)

Where:

x: horizontal position in meters (m)

xi: initial horizontal position in meters (m)

t : time (s)

vx: horizontal velocity in m/s

The equations of uniformly accelerated rectilinear motion of upward (vertical ) for the y axis are:

y= y₀+(v₀y)*t - (1/2)*g*t² Equation (2)

vfy= v₀y -gt Equation (3)

Where:

y: vertical position in meters (m)

y₀ : initial vertical position in meters (m)

t : time in seconds (s)

v₀y: initial vertical velocity in m/s

vfy: final vertical velocity in m/s

g: acceleration due to gravity in m/s²

Data

v₀ = 12.2 m/s , at an angle α=53° above the horizontal

x= 25 m , y=0

Calculation of the time it takes for the ball to hit the ground

We replace data in the equation (1)

x = xi + vx*t

x= 25 m ,xi=0 , vx= v₀*cosα = (12.2 m/s)*cos(53°) =7.34 m/s

25 = 0 + 7.34*t

t= 25 / 7.34

t= 3.406 s

Calculation of the Building height

v₀y = v₀*sinα = (12.2 m/s)*sin(53°) = 9.74 m/s

in t= 3.406 s, y=0

We replace data in the equation (2)

y= y₀ + (v₀y)*t - (1/2)*gt²

0= y₀ + (9.74)*(3.406 )- (1/2)*(9.8)(3.406 )²

0= y₀ + 33.17- -56.84

0= y₀ - 23.67

y₀ = 23.67 m =h: Building height

5 0

2 years ago