two cars on a straight road at time zero are beside each other. the first car, traveling at speed 30 m/s, is passing the second
1 answer:
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The quantity that has a magnitude of zero when the ball is at the highest point in its trajectory is the vertical velocity.
In fact, the motion of the ball consists of two separate motions:
- the horizontal motion, on the x-axis, which is a uniform motion with constant velocity
, where 
- the vertical motion, on the y-axis, which is a uniformly accelerated motion with constant acceleration
directed downwards, and with initial velocity 
. Due to the presence of the acceleration g on the vertical direction (pointing in the opposite direction of the initial vertical velocity), the vertical velocity of the ball decreases as it goes higher, up to a point where it becomes zero and it reverses its direction: when the vertical velocity becomes zero, the ball has reached its maximum height.
In fact, the motion of the ball consists of two separate motions:
- the horizontal motion, on the x-axis, which is a uniform motion with constant velocity
- the vertical motion, on the y-axis, which is a uniformly accelerated motion with constant acceleration
Answer:
a.3.20m
b.0.45cm
Explanation:
a. Equation for minima is defined as:
Given ,
and
:
#Substitute our variable values in the minima equation to obtain :
#draw a triangle to find the relationship between and
.
#where
Hence the screen is 3.20m from the split.
b. To find the closest minima for green(the fourth min will give you the smallest distance)
#Like with a above, the minima equation will be defined as:
, where
given that it's the minima with the smallest distance.
#we then use to calculate
=4.5cm
Then from the equation subtract from
:
Hence, the distance is 0.45cm