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nasty-shy [4]
2 years ago
12

Given the system of constraints, name all vertices of the feasible region. Then find the maximum value of the given objective fu

nction.
Constraints: x is greater than or equal to 0
y is greater than or equal to 0
y is less than or equal to 1/3x+3
5 is greater than or equal to y+x

Objective Function: C=6x-4y

Mathematics
2 answers:
coldgirl [10]2 years ago
8 0
<h2>Answer with explanation:</h2>

The constraints are given by:

                x\geq 0\\\\y\geq 0\\\\y\leq \dfrac{1}{3}x+3\\\\5\geq y+x

  • The first and second constraints tells that the solution must lie in the first quadrant including the origin )

( Since, in the first quadrant both the x and y values are positive )

  • Also, the third inequality is a solid line ( since the inequality is not strict i.e. it is a inequality with a equality sign ) that passes through (-9,0) and (0,3) and the shaded region is towards the origin ( since the inequality passes the zero point test ).
  • The fourth inequality is a solid line ( since the inequality is strict ) that passes through (5,0) and (0,5) and the shaded region is towards the origin ( since the inequality passes the zero point test)

<u>Ques 1)</u>

The feasible region that is formed with the help of these inequality is:

                     Quadrilateral ABCD.

Also, the vertices of the feasible region are:

A(0,3)

B(1.5,3.5)

C(5,0)

D(0,0)

<u>Ques 2)</u>

We know that the objective function is checked at the boundary points of the feasible region i.e. vertices of the feasible region.

The objective function is:

C=6x-4y

  • We check at A(0,3)

              C=6×0-4×3

                 i.e.

               C= -12

  • at B(1.5,3.5)

            C=6×1.5-4×3.5

                  i.e.

                C= -5

  • at C(5,0)

           The value of objective function is:

                 C=6×5-4×0

                        i.e.

                      C=30

  • and at D(0,0)

                      C=6×0-4×0

                          i.e.

                        C=0

The maximum value of the objective function is: 30

and it is obtained at the vertex C(5,0)

MArishka [77]2 years ago
6 0
Attached the solution and work.

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