Michael and Jacob are standing on two docks that are 20 miles apart. They are watching a ship that is out in the ocean. The angl
e between the dock and the line connecting Michael and the ship is 48°, and the angle between the other dock and the line connecting Jacob and the ship is 37°.
If the ship can travel to either dock, which dock would be closest? Explain your answer.
A.) Michael’s dock would be closer because the angle opposite is smaller.
B.) Jacob’s dock would be closer because the angle opposite is smaller.
C.) Michael’s dock would be closer because the docks are 20 miles apart.
D.) Jacob’s dock would be closer because the docks are 20 miles apart.
If the ship can travel to either dock, which dock would be closest? Explain your answer.
A.) Michael’s dock would be closer because the angle opposite is smaller.
B.) Jacob’s dock would be closer because the angle opposite is smaller.
C.) Michael’s dock would be closer because the docks are 20 miles apart.
D.) Jacob’s dock would be closer because the docks are 20 miles apart.
2 answers:
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Answer:
0.335
Step-by-step explanation:
1. There is a 30 percent chance of a flight being delayed because of icy weather ,then the probability of being delayed is 0.3 and of being not delayed is 0.7.
2. If a flight is delayed because of icy weather, there is a 10 percent chance the flight will also be delayed because of a mechanical problem, then the probability of being delayed is 0.1 and the probabilty of not being delayed is 0.9.
3. If a flight is not delayed because of icy weather, there is a 5 percent chance that it will be delayed because of a mechanical problem (MP), then the probability of being delayed is 0.05 and the probabilty of not being delayed is 0.95. (See attached probability tree)
Delayed of icy weather - 0.3
Delayed of MP when weather is not icy - 0.7·0.05=0.035
Now, if one flight is selected at random from the airport in January, the probability that the flight selected will have at least one of the two types of delays is
0.3+0.035=0.335
Answer:
Step-by-step explanation:
For the random variable we define the possible values for this variable on this case
. We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:
We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable like this:
For the distribution of we need to take in count that we are finding a conditional distribution.
given
, for this case we see that
, so then exist
ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:
And if we want to find the joint probability we just need to do this:
And if we multiply the probabilities founded we got: