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Tamiku [17]
2 years ago
5

Some isotopes of elements are unstable and decay into other, more stable isotopes over time. for example, it takes 153 years for

half of a sample of silicon (si) atoms with 14 protons, 14 electrons, and 18 neutrons to decay. what is the name of this specific silicon isotope.
a. silicon-14
b. silicon-32
c. silicon-46
d. silicon-153
Chemistry
1 answer:
Wewaii [24]2 years ago
6 0

The correct answer is option a, silicon-14

Number of electrons = 14

Number of protons = 14

Number of neutrons = 18

Since atomic number is equal to the number of protons, the atomic number of this specific silicon isotope is 14.

Also, mass number is equal to number of protons and number of neutrons. So mass number so this specific silicon isotope is 14 + 18 = 32

The name of this specific silicon isotope is silicon-14.

Silicon-14 is represented as ³²Si₁₄

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<u>Answer:</u> The value of K_c for 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g) reaction is 5.13\times 10^2

<u>Explanation:</u>

We are given:

Initial moles of nitrogen gas = 1.30 moles

Initial moles of hydrogen gas = 1.65 moles

Equilibrium moles of ammonia = 0.100 moles

Volume of the container = 1.00 L

For the given chemical equation:

                N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

<u>Initial:</u>            1.30       1.65

<u>At eqllm:</u>       1.30-x    1.65-3x             2x

Evaluating the value of 'x'

\Rightarrow 2x=0.100\\\\\Rightarrow x=0.050mol

The expression of K_c for above equation follows:

K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}

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Equilibrium moles of hydrogen gas = (1.65-x)=(1.65-0.05)=1.60mol

Putting values in above expression, we get:

K_c=\frac{(0.100)^2}{1.25\times (1.60)^3}\\\\K_c=1.95\times 10^{-3}

Calculating the K_c' for the given chemical equation:

2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

K_c'=\frac{1}{K_c}\\\\K_c'=\frac{1}{1.95\times 10^{-3}}=5.13\times 10^2

Hence, the value of K_c for 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g) reaction is 5.13\times 10^2

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