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Dmitrij [34]
2 years ago
6

Two rectangles are similar. One has a length of 12 cm and a width of 9 cm, and the other has a width of 8 cm. Find the length of

the second rectangle. Round to the nearest tenth if necessary. 8 cm 12.3 cm 6 cm 10.7 cm
Mathematics
1 answer:
Serhud [2]2 years ago
7 0
Use an equation of ratios to solve this:

12 cm             9 cm
----------     =   ---------
    x                 8 cm

Cross multiplying, 9x = 96, and x = 32/3 cm   (10 2/3 cm).
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APEX HELP ASAP!!!!
oee [108]
<span>1. The two boats picked for the trip are the steamboat and the tall ship. Let us assume that we will take the steamboat going to the island, and then we will take the tall ship for the return trip. We will then relate the distances travelled by both ships to each other.

2. We know that the steamboat takes five hours to complete the trip. The tall ship takes more time, at ten hours to complete the trip. We do not have the exact speeds of the steamboat or of the tall ship, but we do know that the tall ship is 10 knots slower than the steamboat. We likewise do not know the exact distance travelled by either ship, but we do know that both travel the same distance. We want to find out how fast each boat travels. We expect the answers to be in knots, with a difference of 10.

3. We know that distance is equivalent to the product of speed of a boat multiplied by the time of travel. For the trip going to the island, we will use the steamboat. Let its speed be x knots (equivalent to x nautical miles per hour), and let the distance going to the island be d nautical miles. Given that the time takes is 5 hours, this means that d = 5x.

4. If we let x be the speed of the boat you are taking to the island (the steamboat), then we know that the speed of the other boat (the tall ship) is 10 knots less than the steamboat's. So the speed of the tall ship (for the return trip) is (x - 10) knots.

5. Similar to part 3: we will multiply speed by time to determine the distance from the island. From part 4, we have determined that the speed of the tall ship to be used in returning is (x - 10) knots. Meanwhile, the given in the problem says that the tall ship will take 10 hours to make the trip. Therefore the distance will be equal to d = 10(x - 10) = 10x - 100 nautical miles.

6. We can assume that the distance travelled going to the island is the same distance travelled coming back. Therefore, we can equate the formula for distance from part 3 for the steamboat, to the distance from part 5 for the tall ship.
5x = 10x - 100

7. Solving for x: 5x = 10x - 100
-5x = -100
x = 20
Since x is the speed of the steamboat, x = 20 means that the steamboat's speed is 20 knots.

8. We determined in part 4 that the speed of the second boat (in our case, the tall ship) is (x - 10) knots. Since we have calculated in part 7 that the steamboat travels at x = 20 knots, then the speed of the tall ship is (x - 10) = 20 - 10 = 10 knots.</span>
7 0
2 years ago
Casey needed to move 23 huge boxes from his truck to the loading dock. His forklift could only hold three boxes at once. How man
miss Akunina [59]

Answer:

8

Step-by-step explanation:

Since the forklift has a maximum capacity of three boxes per trip, simply divide the total number of boxes (23 boxes) by three and round up to the nearest whole unit to find the number of trips required:

n=\frac{23}{3}=7.667

Casey had to visit the dock 8 times. He moved three boxes in seven trips and two boxes in one trip.

6 0
2 years ago
Daisy gave 1/2 of her lanzones to Nuel. Nuel gave 1/3 of the lanzones he received to Ronnie and Ronnie gave 1/4 of what he recei
enot [183]
Assuming all of them had the same amount at the start

3 0
2 years ago
Really important please help #8
Paladinen [302]
B is the answer! Enjoy getting it correct!! :)
5 0
2 years ago
A police car's siren operates at a frequency of 2,000 Hz. What frequency would a stationary listener observe if the police car i
SpyIntel [72]

we can use formula

f_L=f_s(\frac{v_a-v_p}{v_a+v_p} )

where

fL is listener frequency

fs is siren frequency

va is the speed of sound in air

vs is police car speed

so, we have

f_s=2000Hz

v_a=345m/s

v_p=65mph

now, we can change it into m/s

v_p=65*\frac{1609}{3600}m/s

v_p=29.05139m/s

now, we can plug it

f_L=2000(\frac{345-29.05139}{345+29.05139} )

f_L=1689.33263Hz..............Answer

3 0
2 years ago
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