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Jet001 [13]
2 years ago
3

Will mark Brainliest!! Watson, a mountaineer, attempts to jump over a ravine that is 7 meters wide and 10 meters deep within 2 s

econds to escape an approaching avalanche. Calculate the minimum speed with which he should attempt the jump so that he safely gets to the other side of the ravine.
Physics
2 answers:
Sveta_85 [38]2 years ago
6 0
V=distance/time
v=7m/2s
v=3.5m/s
amm18122 years ago
6 0

Answer:

Watson's minimum speed, s = 3.5 m/s

Explanation:

It is given that, Watson, a mountaineer attempts to jump over a ravine that is 7 meters wide and 10 meters deep within 2 seconds to escape an approaching avalanche.

We have to find the minimum speed with which he should attempt the jump so that he safely gets to the other side of the ravine.

Speed is given by :

s=\dfrac{d}{t}

d is the distance, d = 7 m

s=\dfrac{7\ m}{2\ s}

s = 3.5 m/s

Hence, his minimum speed so that he safely gets to the other side of the ravine is 3.5 m/s

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Decreased by a factor of 4.5

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So when R is tripled and mass is doubled, we have the following ratio of the new gravity over the old ones:

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8 0
2 years ago
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Therefore, the initial momentum of block B, mu = 0

According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.

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3 0
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so force will be towards Right

7 0
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