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victus00 [196]
2 years ago
7

Question help a smoke jumper jumps from a plane that is 19001900 ft above the ground. the function h equals negative 16 t square

d plus 1900h=−16t2+1900 gives the​ jumper's height h in feet during the free fall at t seconds.
a. how long is the jumper in free fall if the parachute opens at 1000​ ft?
b. how long is the jumper in free fall if the parachute opens at 940940 ​ft?
c. what is a reasonable domain and range for the function​ h?
Physics
1 answer:
Vesna [10]2 years ago
3 0

A. Starting at 1900 ft, so if he opened his parachute at 1000 ft, therefore this means that h = 1000:

<span> h = - 16t^2 + 1900</span>

1000 = - 16 t^2 + 1900

t = 7.5 seconds

 

B. So we have h = 940

940 = - 16 t^2 + 1900

t = 7.746 seconds

 

C. The domain will always be time and since time starts at zero, so it is the initial point for h:

<span>h =  - 16(0)^2 + 1900</span>

h = 1900

 

We also know that at lowest point h = 0, so the last value of t is:

<span>0 =  - 16 t^2 + 1900</span>

t = 10.897 seconds

Therefore

domain: (0, 10.897)

<span>range: (1900, 0)</span>

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fomenos

Answer: 580 N

Refer to attached figure.

The angle of inclination is 22 degrees

weight (gravitational force) acts downwards.

Normal force is a contact force which acts perpendicular to the point of contact.

The horizontal component (mg cos 22 ) balances the normal force and the vertical component balances the frictional force.

Gravitational force on an object = mg

The normal force N= mg cos 22

\Rightarrow mg =\frac{N}{cos22}=\frac{538 N}{0.927}=580 N





8 0
2 years ago
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A stone is thrown into a pond. Five waves were made from the same source in 10 seconds.
lina2011 [118]

Answer:

The Frequency of the wave is 0.2Hertz

The period is 2seconds

Explanation:

We are asked to find the frequency and period

Frequency is the number of oscillations completed in one seconds

If five waves were made from the same source in 10 seconds, hence;

Frequency = number of oscillation/Time

Frequency = 5/10

Frequency = 0.5Hertz

Next is to get the period

Period = 1/Frequency

Period = 1/0.5

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3 0
2 years ago
A Roller Derby Exhibition recently came to town. They packed the gym for twoconsecutive weekend nights at South's field house. O
Alla [95]

Answer:

14.4 m/s

Explanation:

mass of Anna (Ma) = 68 kg

speed of Anna (Va) = 17 m/s

mass of SandraDay (Ms) = 76 kg

speed of SandraDay (Vs) = 12 m/s

We can find their speed (V) immediately after collision from the conservation of momentum where

(Ma x Va) + (Ms + Vs) = (Ma + Ms) x V

where V = speed immediately after collision

(68 x 17) + (76 + 12) = (68 + 76) x V

2068 = 144 V

V = 2068 / 144 = 14.4 m/s

8 0
2 years ago
Sally finds herself stranded on a frozen pond so slippery that she can't stand up or walk on it. To save herself, she throws one
8_murik_8 [283]

Answer:

a) 2.5 m/s. (In the opposite direction to the direction in which she threw the boot).

b) The centre of mass is still at the starting point for both bodies.

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Explanation:

Linear momentum is conserved.

(mass of boot) × (velocity of boot) + (mass of sally) × (velocity of Sally) = 0

5×30 + 60 × v = 0

v = (-150/60) = -2.5 m/s. (Minus inicates that motion is in the opposite direction to the direction in which she threw the boot).

b) At time t = 10 s,

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Taking the starting point for both bodies as the origin, and Sally's direction as the positive direction.

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The centre of mass is still at the starting point for both bodies.

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Hope this Helps!!!

7 0
2 years ago
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010) Identify the true statement. Group of answer choices The height of waves is determined by wind strength and fetch. Wave bas
AlekseyPX

Answer:

The height of the wave is determined by the wind strength and fetch.

Explanation:

The height of the wave is determined by the wind strength and fetch.

The more the strength and the more the fetch size the more will be the height of the wave.

Remember as the wave approaches the coast its wavelength decreases and the wave height increases, whereas when the wave goes away from the coast its wavelength increases and height decreases.

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