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Step2247 [10]
2 years ago
15

Identify the situations that have an unbalanced force. Check all that apply. A baseball speeds up as it falls through the air. A

soccer ball is at rest on the ground. An ice skater glides in a straight line at a constant speed. A bumper car hit by another car moves off at an angle. A balloon flies across the room when the air is released.
Physics
2 answers:
viktelen [127]2 years ago
5 0
<span>A baseball speeds up as it falls through the air.
Yes.  Forces on the balloon are unbalanced. 
The balloon is speeding up, so we know that the downward force
of gravity is stronger than the upward force of air resistance.

A soccer ball is at rest on the ground.
No. The ball is not accelerating, so we know that the forces on it
are balanced.
The downward force of gravity on the ball and the upward force
of the ground are equal.


An ice skater glides in a straight line at a constant speed.
No. The skater's speed and direction are not changing, so he is not
accelerating.  That tells us that the forces on him are balanced.

A bumper car hit by another car moves off at an angle.
Yes.  The direction in which the car was moving changed. 
That's acceleration, so we know that the forces on it are unbalanced,
at least at the moment of impact. 

A balloon flies across the room when the air is released.
Yes.  The balloon was not moving. But when the little nozzle was
opened, it started to zip around the room.  So its speed changed.
And, as it goes bloozing around the room, its direction keeps changing too. 
There's a whole lot of acceleration going on, so we know the forces on it
are unbalanced.</span>
Norma-Jean [14]2 years ago
5 0
A bumper car hit by another car moves off at an angle.<span>A balloon flies across the room when the air is released.
</span><span>A baseball speeds up as it falls through the air.
</span>
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A single slit, which is 0.050 mm wide, is illuminated by light of 550 nm wavelength. What is the angular separation between the
likoan [24]

Answer:

The separation between the first two minima on either side is 0.63 degrees.

Explanation:

A diffraction experiment consists on passing monochromatic light trough a small single slit, at some distance a light diffraction pattern is projected on a screen. The diffraction pattern consists on intercalated dark and bright fringes that are symmetric respect the center of the screen, the angular positions of the dark fringes θn can be find using the equation:

a\sin \theta_n=n\lambda

with a the width of the slit, n the number of the minimum and λ the wavelength of the incident light. We should find the position of the n=1 and n=2 minima above the central maximum because symmetry the angular positions of n=-1 and n=-2 that are the angular position of the minima below the central maximum, then:

for the first minimum

a\sin \theta_1=(1)\lambda

solving for θ1:

\theta_1=\arcsin (\frac{\lambda}{a})=\arcsin (\frac{550\times10^{-9}}{0.05\times10^{-3}})

\theta_1=0.63 degrees

for the second minimum:

a\sin \theta_2=(2)\lambda

\theta_2=\arcsin (\frac{2\lambda}{a})=\arcsin (\frac{2*550\times10^{-9}}{0.05\times10^{-3}})

\theta_2=1.26 degrees

So, the angular separation between them is the rest:

\Delta \theta =1.26-0.63

\Delta \theta=0.63

4 0
2 years ago
What is the magnitude of the force a 1.5 x 10-3 C charge exerts on a 3.2 x 10-4 C charge located 1.5 m away?
sweet [91]
The magnitude of the force<span> a 1.5 x 10-3 C charge exerts on a 3.2 x 10-4 C charge located 1.5 m away is 1920 Newtons. The formula used to solve this problem is:

F = kq1q2/r^2

where:
F = Electric force, Newtons
k = Coulomb's constant, 9x10^9 Nm^2/C^2
q1 = point charge 1, C
q2 = point charge 2, C
r = distance between charges, meters

Using direct substitution, the force F is determined to be 1920 Newtons.</span>
7 0
2 years ago
The late news reports the story of a shooting in the city. Investigators think that they have recovered the weapon and they run
Gemiola [76]

Answer:

50000 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of bullet = 0.050 kg

velocity (v) = 400 m/s

Distance (s) = 0.080 m

Force (F) =?

Next, we shall determine the acceleration of the bullet. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 400 m/s

Distance (s) = 0.080 m

Acceleration (a) =?

v² = u² + 2as

400² = 0 + (2 × a × 0.08)

160000 = 0 + 0.16a

160000 = 0.16a

Divide both side by 0.16

a = 160000 / 0.16

a = 1×10⁶ m/s²

Finally, we shall determine the force exerted by the bullet on the target. This can be obtained as follow:

Mass (m) of bullet = 0.050 kg

Acceleration (a) of bullet = 1×10⁶ m/s²

Force (F) =?

F = ma

F = 0.050 × 1×10⁶

F = 50000 N

Thus, the bullet exerted a force of 50000 N on the target.

7 0
2 years ago
A 3.0-kilogram object is acted upon by an impulse having a magnitude of 15 newton•seconds. What is the magnitude of the object’s
Ilia_Sergeevich [38]
The mass of the object doesn't matter. The change in its momentum is equal to the impulse that changed it ... 15 N-sec.
3 0
2 years ago
A dog travels north for 18 meters, east for 8 meters, South for 27 meters and then west for 8 meters. What is the distance the d
Afina-wow [57]
I'm really not sure if this is right but I'll try.
The distance that the dog traveled is probably all of the distances added up. I would guess that it's 67 meters in total. 
The displacement is a little more tricky but you pretty much have to put a mental map in your head. Since East and West are both 8 meters, they cancel each other out. He travels more southern and that means the displacement is 9 meters south of his original location
7 0
2 years ago
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