Ow many coulombs of charge are needed to produce 35.2 mol of solid zinc?
2 answers:
Answer:
6.79 × 10⁶ c
Explanation:
Zn can be produced from the electrolysis of an aqueous solution of a Zn salt. The reduction reaction is:
Zn²⁺(aq) + 2 e⁻ → Zn(s)
We can establish the following relations.
- 1 mol of Zn is produced when 2 moles of e⁻ are gained.
- 1 mole of e⁻ has a charge of 96468 c (Faraday's constant).
The charge needed to produce 35.2 mol of Zn is:
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Answer:
1) Net ionic equation :
2) 0.765 M is the molarity of the carbonic acid solution.
Explanation:
1) In aqueous carbonic acid , carbonate ions and hydrogen ion is present.:
..[1]
In aqueous potassium hydroxide , potassium ions and hydroxide ion is present.:
..[2]
In aqueous potassium carbonate , potassium ions and carbonate ion is present.:
..[3]
From one:[1] ,[2] and [3]:
Cancelling common ions on both sides to get net ionic equation :
2)
To calculate the concentration of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
0.765 M is the molarity of the carbonic acid solution.
<u>Answer:</u> The value of for the reaction at 690 K is 0.05
<u>Explanation:</u>
We are given:
Initial pressure of = 1.0 atm
Total pressure at equilibrium = 1.2 atm
The chemical equation for the decomposition of phosgene follows:
Initial: 1 - -
At eqllm: 1-x x x
We are given:
Total pressure at equilibrium = [(1 - x) + x+ x]
So, the equation becomes:
The expression for for above equation follows:
Putting values in above equation, we get:
Hence, the value of for the reaction at 690 K is 0.05