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RideAnS [48]
2 years ago
5

In which of the molecules does the central atom utilize d orbitals to form hybrid orbitals?

Chemistry
1 answer:
irina1246 [14]2 years ago
8 0
Well, when there is a tetrahedral shaped molecule involve itself in a double bond, it doesn't have any more p orbitals to form the pi bond. because sp3 uses all 3 p orbitals, it would need to pull an orbital from the d shell.

an example molecule would be PO4 3-
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A flask containing helium gas is connected to an open-ended mercury manometer. The open end is exposed to the atmosphere, where
stepladder [879]

Answer:

726 torr

Explanation:

Generally, atmospheric pressure can be measured using a manometer which is in form of a U-shaped tube. In addition, 1 mm Hg is equivalent to 1 torr. Therefore, 752 torr is equivalent to 752 mm Hg. Therefore, the total pressure will be equivalent to the atmospheric pressure (mm Hg) + the mercury height.

In this case, the mercury height = -26 mm

Thus:

The helium pressure = 752 - 26 = 726 mm Hg

This is also equivalent to 726 torr

8 0
2 years ago
Give the major organic product of the reaction of o-methylaniline with benzenediazonium chloride [(phn≡n)+ cl-].
Wewaii [24]
Benzene diazonium salt reacts by coupling with activated aromatic rings as aniline and phenol and in this case diazonium acts as weak electrophile and react with substitution on para position according to the following reaction:

7 0
2 years ago
If water’s density is 1.0 g/mL, then would the perfume be more or less dense than water? Would the perfume float on top or sink
Alex17521 [72]

Answer:

usually the perfumes are made of aromatic hydrocarbons invloving

cetone, ethanol, benzaldehyde, formaldehyde, limonene, methylene chloride, camphor, ethyl acetate, linalool and benzyl alcohol. which have density lower than the water hence they will float on the top of the water.

Hope this helps you

Explanation:

5 0
2 years ago
If a swimming pool contains 2,850 kiloliters (kL) of water, how many gallons (gal) of water does it contain? (1 gal = 3.785 L)
siniylev [52]

we are given

a swimming pool contains 2,850 kiloliters (kL) of water

2,850 kiloliters (kL)=2850000L

we know that

1gal=3.785L

3.785L=1gal

Firstly , we will find for 1L

1L=\frac{1}{3.785}gal

now, we can multiply both sides by 2850000

2850000*1L=2850000*\frac{1}{3.785}gal

2850000L=2850000*\frac{1}{3.785}gal

2850000L=752972.25892gal

so,

a swimming pool contains 752972.25892gal of water...........Answer


6 0
2 years ago
Read 2 more answers
A compound is 2.00% H by mass, 32.7% S by mass, and 65.3% O by mass. What is its empirical formula? The second step is to calcul
Free_Kalibri [48]
Lets take 100 g of this compound,
so it is going to be 2.00 g H, 32.7 g S and 65.3 g O.

2.00 g H *1 mol H/1.01 g H ≈ 1.98 mol H
32.7 g S *1 mol S/ 32.1 g S ≈ 1.02 mol S
65.3 g O * 1 mol O/16.0 g O ≈ 4.08 mol O

1.98 mol H : 1.02 mol S : 4.08 mol O = 2 mol H : 1 mol S : 4 mol O

Empirical formula
H2SO4
8 0
1 year ago
Read 2 more answers
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