when water boils, it becomes steam .its particles spread out and occupy a greater volume. has its density increased or decreased
2 answers:
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Answer:
Explanation:
Let 'F₁' and 'F₂' be the forces applied by left and right wires on the bar as shown in the diagram below.
Now, the horizontal and vertical components of these forces are:
As the system is in equilibrium, the net force in x and y directions is 0 and net torque about any point is also 0. Therefore,
Now, let us find the net torque about a point 'P' that is just above the center of mass at the upper edge of the bar.
At point 'P', there are no torques exerted by the F₁x and F₂x nor the weight of the bar as they all lie along the axis of rotation.
Therefore, the net torque by the forces will be zero. This gives,
But,
Therefore,
We know,
∴
- Answer:
Velocity of Sam =
and velocity of Abigail =
Explanation: Consider Vs as sam velocity and Va as bigail velocity. Now consider the north as positive x and the east as positive y for our reference. Before collision, their velocity vectors can be represented as
= Vs i
=Va j Now after collision their velocity vectors are given as
= 6 cos 37 i + 6 sin 37 j = 4.79 i + 3.61 j
= 9 cos 23 i + 9 sin 23 j = 8.28 i - 3.52 j As we know in the absence of external force the momentum before and after collision will remain the same therefore P1 = P2 ∴ P = mv Momentum = mass x velocity
As sliding is on frictionless surface therefore before and after the collision, momentum remains conserved in the absence of external force. we can write it as
Now putting values we get 80 x Vs + 50 x 0 = 80 x 4.79 + 50 x 8.28 (First Consider horizontal vector components) Velocity of sam before collision= Vs = 9.97
Now consider vertical vector components 80 x 0 + 50 x Va = 80 x 3.61 + 50 x (-3.52) (Before Collision direction opposite so put negative sign) velocity of abigail before collision = Va = 2.26
Answer:
We can relate the kinetic energy of the particle to the potential difference between the plates by following equations:
Work energy theorem:
So,
If the distance is doubled and the potential difference is halved, then
Explanation:
As can be seen from the relationship between kinetic energy and the potential difference, the distance between the plates has no effect on the relation between kinetic energy and the potential difference. Since the charge of the second particle is equal to that of the first one, the new kinetic energy would be half of the first kinetic energy.