A parcel is traveling on a horizontal conveyer belt moving at 1 meter/second. At the end of the conveyor belt, the parcel lands
1 answer:
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Answer:
Approximately at that distance from the center of the planet.
Option A) The low value of near the cloud top of Saturn is possible because of the low density of the planet.
Explanation:
The value of on a planet measures the size of gravity on an object for each unit of its mass. The equation for gravity is:
,
where
.
is the mass of the planet, and
is the mass of the object.
To find an equation for , divide the equation for gravity by the mass of the object:
.
In this case,
, and
.
Calculate based on these values:
.
Saturn is a gas giant. Most of its volume was filled with gas. In comparison, the earth is a rocky planet. Most of its volume was filled with solid and molten rocks. As a result, the average density of the earth would be greater than the average density of Saturn.
Refer to the equation for :
.
The mass of the planet is in the numerator. If two planets are of the same size, would be greater at the surface of the more massive planet.
On the other hand, if the mass of the planet is large while its density is small, its radius also needs to be very large. Since is in the denominator of
, increasing the value of
while keeping
constant would reduce the value of
. That explains why the value of
near the "surface" (cloud tops) of Saturn is about the same as that on the surface of the earth (approximately
.
As a side note, likely refers to the distance from the center of Saturn to its cloud tops. Hence, it would be more appropriate to say that the value of
near the cloud tops of Saturn is approximately
.
Answer:
Explanation:
Pressure is measured is here p is pressure
is density and h is height
We have given pressure acceleration due to gravity
height =1.163 m
Answer:
v = 2.21 m/s
Explanation:
The foreman had released the box from rest at a height of 0.25 m above the ground.
We need to find the speed of the crate when it reaches the bottom of the ramp. Let v is the velocity at the bottom of the ramp. It can be calculated using conservation of energy as follows :
So, its velocity at the bottom of the ramp is 2.21 m/s.