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Sergeu [11.5K]
2 years ago
7

What relation does not have an initial value of 50

Mathematics
1 answer:
Mamont248 [21]2 years ago
4 0
I guess itz B because with the rest, a number can be added to get exactly 50. Example C. y= 50x. x could be 1 which is still 50 and D. y=50-x and x could be 0 which is still 50 whiles A. y=50 remains 50

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tim drives at an average speed of 80km per hour for 3 hours 45 minutes work out how many kilometres tim drives
krek1111 [17]
Speed  = distance / time
3 hours 45 minutes = 3.75 hours
80 = distance / 3.75

distance = 80 * 3.75  =  300 kms Answer
4 0
2 years ago
Information about five planets is shown in the table below.
Karo-lina-s [1.5K]

Answer:

(a)Jupiter

(b)24.4 km

(c)1.33 \times 10^{27}$ kg

Step-by-step explanation:

<u>Part A</u>

The planet with the greatest ma.ss is Jupiter.

It has a ma.ss of 1.898 X 10^{27}$ kg

<u>Part B</u>

The diameter of Mercury = 4.88 X 10

Radius = Diameter/2

Therefore:

Radius of Mercury

=\dfrac{4.88 X 10}{2}\\ =2.44 X 10\\=24.4$ km

<u>Part C</u>

M$a.ss of Saturn = 5.68 X 10^{26}\\$Mass of Jupiter = 1.898 X 10^{27}\\$Difference in their ma.ss =(1.898 X 10^{27})-(5.68 X 10^{26})\\=1.33 \times 10^{27}$ kg

4 0
2 years ago
The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find
fenix001 [56]

Answer:

y2 = (6x + 7)/36 + (Dx + E)e^x

Step-by-step explanation:

The method of reduction of order is applicable for second-order differential equations.

For a known solution y1 of a 2nd order differential equation, this method assumes a second solution in the form Uy1 which satisfies the said differential equation. It then assumes a reduced order for U'' (w' = U'').

The differential equation becomes easy to solve, and all that is left are integration and substitutions.

Check attachments for the solution to this problem.

6 0
2 years ago
What is the value of x in the equation 25x2 = 16?
valentina_108 [34]
<span>25x2 = 16
x^2 = 16/25
</span>x^2 = 4^2/5^2
<span>x = 4/5

</span>
7 0
2 years ago
Read 2 more answers
On two investments totaling $6,000, Brian lost 7% on one and earned 8% on the other. If his net annual receipts were $420, how m
lianna [129]

Answer:

the amount of money invested at the rate of 7% is $400

the amount of money invested at the rate of 8%. Is $5600

Step-by-step explanation:

Let x represent the amount of money invested at the rate of 7%.

Let y represent the amount of money invested at the rate of 8%.

The total amount of money that Brian invested is $6000. This means that

x + y = 6000

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time

Considering the investment at the rate at 7%,

P = x

R = 7%

T = 1

I = (x × 7 × 1)/100 = 0.07x

Considering the investment at the rate of 8%,

P = y

R = 8

T = 1

I = (y × 8 × 1)/100 = 0.08y

If his net annual receipts were $420, it means that

0.08y - 0.07x = 420 - - - - - - - - -1

Substituting x = 6000 - y into equation 1, it becomes

0.08y - 0.07(6000 - y) = 420

0.08y - 420 + 0.07y = 420

0.08y + 0.07y = 420 + 420

0.15y = 840

y = 840/0.15 = 5600

x = 6000 - y = 6000 - 5600

x = 400

8 0
2 years ago
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