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Leya [2.2K]
2 years ago
15

Elle wanted to test how temperature affects the rate of evaporation. She had three setups:

Chemistry
1 answer:
Pie2 years ago
5 0

Answer:

Temperature

Explanation:

Here the factor that Elle is controlling is the temperature. So temperature here is the independent variable and the dependent variable is the rate of evaporation of water.  Independent variable is controlled during the experiment setup and the outcome of the dependent variable depends on the independent variable.

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Solid aluminum metal and diatomic chlorine gas react spontaneously to form a solid product. Give the balanced chemical equation
ValentinkaMS [17]

When solid aluminum metal is reacted with diatomic chlorine gas, solid aluminum chloride is formed. This reaction is an example of synthesis or chemical combination in which two elements, aluminum and chlorine combine to form a new compound aluminum chloride.

Word equation: Aluminum (s)+ Chlorine (g)---> Aluminum chloride(s)

Molecular formula of the product formed is AlCl_{3}.

Therefore the balanced chemical equation representing the reaction of solid aluminum with gaseous dichlorine can be represented as,

2Al(s) + 3Cl_{2}(g)-->2AlCl_{3}(s)

8 0
2 years ago
Which reactants would lead to a spontaneous reaction?
balandron [24]

Answer: Option (b) is the correct answer.

Explanation:

The elements which have excess or deficiency of electrons will react readily.

Atomic number of Mn is 25 and electronic configuration of Mn^{2+} is [Ar]4s^{0}3d^{5}. This configuration is stable.

Atomic number of Cr is 24 and electronic configuration of Cr is [Ar]4s^{1}3d^{5}. This configuration is not stable.

Atomic number of Fe is 26 and electronic configuration of Fe is [Ar]4s^{2}3d^{6}. This configuration is stable.

Atomic number of Cu is 29 and electronic configuration of Cu^{2+} is [Ar]4s^{0}3d^{9}. This configuration is not stable.

Atomic number of Al is 13 and electronic configuration of Al is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}. This configuration is not stable.

Atomic number of Ba is 56 and electronic configuration of Ba^{2+} is [Kr]4d^{10}5s^{2}5p^{6}. This configuration is stable.

Atomic number of Mg is 12 and electronic configuration of Mg^{2+} is 1s^{2}2s^{2}2p^{6}. This configuration is stable.

Atomic number of Sn is 50 and electronic configuration of Sn is [Kr]4d^{10}5s^{2}5p^{2}. This configuration is stable.

Thus, we can conclude that out of the given options, only Fe and Cu^{2+} reactants would lead to a spontaneous reaction as they have incomplete sub-shells. Therefore, in order to gain stability they will readily react.


8 0
2 years ago
10 points) Given the following two half-reactions, write the overall reaction in the direction in which it is product-favored, a
IceJOKER [234]

Answer:

The over all reaction :

2Fe^{3+}(aq)+Pb(s)\rightarrow 2Fe^{2+}(s)+Pb^{2+}(aq)  

The standard cell potential of the reaction is 0,.897 Volts.

Explanation:

Reduction at cathode :

Fe^{3+}(aq)+e^-\rightarrow Fe^{2+}(s)..[1]  

E^o_{Fe^{3+}/Fe^{2+}}=0.771 V

Reduction potential of Fe^{3+} to Fe^{2+}=0.771 V

Oxidation at anode:

Pb(s)\rightarrow Pb^{2+}(aq)+2e^-.[2]

E^o_{Pb^{2+}/Pb}=-0.126 V

Reduction potential of Pb^{3+} to Pb=-0.126 V

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

Putting values in above equation, we get:

E^o_{cell}=E^o_{Fe^{3+}/Fe^{2+}}-E^o_{Pb^{2+}/Pb}

=0.771 V-(-0.126 )=0.897 V

The over all reaction : 2 × [1] + [2]

2Fe^{3+}(aq)+Pb(s)\rightarrow 2Fe^{2+}(s)+Pb^{2+}(aq)  

The standard cell potential of the reaction is 0,.897 Volts.

7 0
2 years ago
A 5 mole sample of liquid acetone is converted to a gas at 75.0°C. If 628 J are required to raise the temperature of the liquid
Shkiper50 [21]
The total energy can be found by adding the different energies:
628 + 15,600 + 712
= 16.94 kJ
4 0
2 years ago
Hydrazine (N2H4) and dinitrogen tetroxide (N2O4) form a self-igniting mixture that has been used as a rocket propellant. The rea
Alexxx [7]

Answer:

Explanation:

An oxidizing accepts an electron and becomes reduced while a reducing agent loses an electron and become oxidized.

Chemical equation:

1) 2 N₂H₄ + N₂O₄ → 3 N₂ + 4 H₂O

2) Hydrazine ( N₂H₄)  is being oxidized

Dinitrogen tetroxide N₂O₄ is being reduced

3) The reducing agent is Hydrazine ( N₂H₄) and the oxidizing agent is dinitrogen tetroxide (N₂O₄)

5 0
2 years ago
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