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lesya692 [45]
2 years ago
8

Epsom salt is commonly purchased in the pharmacy for a variety of uses, anti-inflammatory, laxative, and cosmetic. epsom salt is

a hydrated salt of magnesium sulfate. if 2.000 g of epsom salt are heated to remove the waters of hydration, 0.977 g of the anhydrous (without water) magnesium sulfate, mgso4, were obtained. calculate the number of waters of hydration, and write the chemical formula of the epsom salt.
Chemistry
2 answers:
Dominik [7]2 years ago
4 0
Epsom salt is MgSO4.
We assume x water of hydration in the crystalline form.

Molecular mass of MgSO4 = 24+32+4*16=120
Molecular mass of MgSO4.xH2O = 120+18x

By proportion, 
2.000/0.977 = (120+18x)/120
Cross multiply
0.977(120+18x) = 120*2.000
from which we solve for x
17.586x+117.24 = 240
x=122.78/17.586
=6.980

Answer: there are 7 water of hydration in Epsom salt, according to the experiment.

Note: more accurate (proper) results may be obtained by using exact values (3-4 significant figures) in the molecular masses.  However, since water of hydration is the nearest integer, using approximate values (to at least two significant figures) suffice.
Anettt [7]2 years ago
3 0

The total weight (MgSO₄ + xH₂O) = 2.000 g

Weight of anhydrous, that is, without water magnesium sulfate = 0.977 g

Weight of xH₂O = 2.000 - 0.977 = 1.023 g

Moles of water = Weight / molecular mass

= 1.023 / 18 = 0.057  

Moles of MgSO₄ = 0.977 / 120.366 = 0.0081

0.0081 mole (0.977) MgSO₄ hydrated with = 0.057 mol of water

1 mole will react with = 7 mol of water

Chemical formula of the Epsom salt = MgSO₄.7H₂O


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<em>Answer:</em>

The order of liquid from top to bottom is as follow

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<em>Density:   </em>

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0,472g ×\frac{1mol}{18,02g} = 2,6193x10⁻² moles H₂O

The ratio of moles H₂O:CuSO₄ is:

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