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2 years ago

Which salt is not derived from a strong acid and a strong soluble base? 1. liclo4 2. csbr2 3. mgcl2 4. ba(no3)2 5. nai?

2 answers:

7 0

<span>3. MgCl2 For each salt, determine what acid and base were used to create it by separating the salt into it's cation and anion. From there, determine the acid and base used to create the salt by adding the appropriate number of hydroxyl group(s) to the cation and hydrogen to the anion. So: LiClO4 -> Li, ClO4 -> LiOH + HClO4. LiOH is a strong base, and HClO4 is a strong acid. CsBr2 -> Cs, Br2 -> CsOH + HBr2 CsOH is a strong base, and HBr2 is a strong acid. MgCl2 -> Mg, Cl2 -> Mg(OH)2 + HCl Mg(OH)2 is not a strong soluble base HCl is a strong acid. Therefore MgCl2 is the correct salt. Ba(NO3)2 -> Ba, NO3 -> Ba(OH)2 + HNO3 Ba(OH)2 is a strong base, and HNO3 is a strong acid. NaI -> Na, I -> NaOH + HI NaOH is a strong base, and HI is a strong acid.</span>

lianna [129]2 years ago

4 0

I believe the answer is MgCl, this is because the bases of group one elements (alkali metals) such as sodium, lithium , and cesium, are all strong bases unlike those of group 2 and group 3. The bases of group one elements ( NaOH, LiOH, CsOH) all readily dissolve in water forming strong soluble base. Then between a base of Ba (Ba(OH)2)and that of Mg, (Mg(OH)2), the one for Ba is more stronger because Ba is more reactive than that of Mg because it is not readily dissolve in water ( less soluble in water to give OH- ions)

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Suppose you have exactly 1 cup (237 g) of hot (100.0 °C) brewed tea in an insulated mug and that you add to it 2.50 × 10² g of i

san4es73 [151]

Answer:

Final Temperature = 298.28 K (25.28°C)

Explanation:

First off, lets least out our parameters (What we were given).

Mass of Tea (Mt) = 237g

Initial temp. of tea (T1) = 100 °C + 273 = 373K (Converting to Kelvin)

Mass of Ice (Mi) = 2.50 × 10² g = 250g

Initial temp. of ice (T1) = -18 °C + 273 = 255K (Converting to Kelvin)

If all the ice melts

Amount of Heat required to melt the ice [H] = Amount of heat required to raise its temperature to 0°C or 273K (Melting point) [H1] + Heat of Fusion [H2]

H1 = MiCΔT

ΔT = T2 - T1 = 255 - 273 = -18K

C = 2.09 J/gK (Specific Heat capacity of Ice)

H1 = 250 * 2.09 * (-18)

H1 = -9405 J

H2 = m·ΔHf

ΔHf = Heat of fusion of ice = 334 J/g

H2 = 250 * 334

H2 = 83500 J

Amount of Heat required to melt the ice [H] = H1 + H2

H = -9405 + 83500 = 74095 J

This means the heat was able to supply 74095 J to the tea.

Final temperature is calculated from:

H = MtCΔT

ΔT = H/MtC

ΔT = 74095/(237 * 4.184)

ΔT = 74095 / 991.61

ΔT = 74.72 K

With a temperature difference of 74. 72 K

Final temperature = Initial temperature - 74.72K

T2 = 373 - 74.74

T2 = 298.28 K (25.28°C)

6 0

2 years ago

A piece of iron (C=0.449 J/g°C) and a piece of gold (C=0.128 J/g°C) have identical masses. If the iron has an initial temperatur

spin [16.1K]

Answer:

The correct answer is B. Since the two metals have the same mass, but the specific heat capacity of iron is much greater than that of gold, the final temperature of the two metals will be closer to 498 K than to 298 K

Explanation:

Iron is hotter and gold is colder, therefore, according to laws of thermodynamics, iron will lose heat to gold until they are at the same temperature.

The specific heat capacity of iron(0.449) is over three times that of gold(0.128). Since masses are equal, this means that each time iron's temperature drops by one degree, the energy released it releases makes gold's temperature increase by more than 3 degrees. So gold's temperature will be climbing much faster than iron's is falling. Meaning they will meet closer to the initial temperature of iron than that of gold

4 0

2 years ago

The pH of 1M MOH solution which is only 10% dissociated.

GaryK [48]

Answer:

asgen

Explanation:

7 0

2 years ago

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The temperature on a distant, undiscovered planet is expressed in degrees B. For example, water boils at 180 ∘ B and freezes at

marin [14]

Answer:

40.3∘C

Explanation:

At planet B;

Water boils = 180∘C

Water freezes = 50∘C

In this planet the temperature difference = 180 - 50 = 130 compared to earth where the temperature difference is; 100 - 0 = 100

This means;

130 ∘C = 100 ∘C

x ∘C = 31 ∘C

x = 31 * 130 / 100

x = 40.3∘C

5 0

2 years ago

3. A 0.500 g sample of nitrogen gas combines with 1.140 g of oxygen gas to form NO2. If the atomic mass of oxygen is 16.000, cal

DedPeter [7]

Answer;

= 18.24

Explanation;

The ratio of N and O in the formula NO2 IS 1:2

Mass of nitrogen gas is 0.500 g

Moles of nitrogen will be;

= 0.500/16 = 0.03125 moles

Therefore;

The moles of Oxygen from the ratio will be;

= 0.03125 × 2 = 0.0625 moles

But; 0.0625 moles is equal to 1.140 g of Oxygen

The atomic number (mass in 1 mole) will be;

= 1.140 /0.0625

= 18.24

Thus the atomic number of Oxygen from the data is 18.24

6 0

2 years ago

Read 2 more answers