Question

8. A 0.500 kg model rocket is initially pushed upwards by a thrust force of 15N. If the force of air resistance is 1.00 N, what is the initial acceleration of the rocket?

Answer 1

Resultant force = ma

15N - 1N = 0.5kg(a)
a = 14/0.5
a = 28 m/s2

Answer 2

Answer:

a = 18.19 $m/s^{2}$

Explanation:

Given

Mass of the rocket m = 0.500 kg

upward force $F_{up}$ = 15 N

Air Resistance $F_{Res}$ = 1.00 N

Solution

Net force = Upward forces - downward forces

Net force = Upward force - (air resistance + weight)

$F_{net} = x_{up} -(F_{Res} +mg )\\\\F_{net} = 15 -( 1 + 0.5 \times 9.81)\\\\F_{net} = 15 - (1+ 4.905)\\\\F_{net} = 9.095$

Net acceleration

$a = \frac{F_{net} }{m} \\\\a = \frac{9.095 }{0.5}\\\\a = 18.19 m/s^{2}$