Given the equation representing a reaction at equilibrium: h2s(aq) ch3nh2(aq) hs(aq) ch3nh3 (aq) according to one acid-base theo
2 answers:
Answer: loses proton and
accepts proton
Explanation: According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
For the given chemical equation:
Here, is loosing a proton, thus it is considered as an acid and after losing a proton, it forms
which is a conjugate base.
And, is gaining a proton, thus it is considered as a base and after gaining a proton, it forms
which is a conjugate acid.
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Correct answer: a. releasing CO2 that dissolves and forms acid in the oceans
The fuels used in automobiles release gases like carbon dioxide, carbon monoxide, oxides of nitrogen and sulfur. Carbon dioxide when dissolved in water forms carbonic acid. So, when the usage of cars is high, these emissions of carbon-dioxide into the atmosphere increase and this leads to the lowering of pH of the oceans as the carbon dioxide present in higher amounts in to atmosphere diffuses into the oceanic waters and form carbonic acid which makes the ocean slightly acidic.
Answer:
Δ
Δ
Explanation:
Hello,
At the first state, the molar volume is:
The volume in both the second and third state:
Now, as it is about an adiabatic process, one remembers the following relationships:
- Next, for the aforesaid volumes and the first pressure, one computes the second pressure as:
- And the temperature:
- Q:
It is clear that the heat for the first process is 0 as it is adiabatic, but for the second one, it is computed as:
Then the total heat:
- The work for the first process is:
It is clear that the second process is isochoric, so the work here is zero, thus, the total work is:
- For the two processes, ΔU becomes the same value since the system returns to the initial temperature, so ΔU total is 0, thus, for each process, one's got:
- Finally, the total enthapy is also 0 due to same aforesaid reason, thus, each enthalpy is:
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