Question

What is the molarity of solution made by diluting 26.5 ml of 6.00m hno3 to a volume of 250 ml?

Answer 1

The  molarity  of    solution  made  by  diluting   26.5ml  of  6.0ml  hno3  to  a  volume  of  250ml  is  calculated  using  the  following  formula

M1V1  =  M2V2,   where 

M1  =  molality  1 (6.00m)
V1=  volume  1 (26.5  ml)
M2 = molarity  2(?)
v2=volume  2   (250)

M2 =  M1V1/V2

M2=  6  x26.5/250  =  0.636 M

Answer 2

Answer: The molarity of the diluted solution will be 0.636 M

Explanation:

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted solution

We are given:

$M_1=6M\\V_1=26.5mL\\M_2=?M\\V_2=250mL$

Putting values in above equation, we get:

$6\times 26.5=M_2\times 250\\\\M_2=0.636M$

Hence, the molarity of the diluted solution will be 0.636 M