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Dafna11 [192]
2 years ago
11

A vehicle ___________ occurs when the driver begins to back up and is unaware that a person is behind the vehicle.

Physics
2 answers:
kap26 [50]2 years ago
8 0

Answer:

back over is the correct answer

jeka942 years ago
6 0
I don't know accident?
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What size force does the femur exerts on the kneecap if the tendons are oriented as in the figure and the tension in each tendon
sesenic [268]
 Sum of horizontal forces<span> = 0 
F(horizontal) = 60 cos 42
                     = 44.58 

</span>Sum of vertical forces = 0 <span>
F(vertical) = 60 - 60 sin 42
                 = 19.85 

F = sqrt (Fh² + Fv²)
   = sqrt (44.58² + 19.85²)
   = 48.8 N</span>
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2 years ago
Andre really likes his new car, and he knows it has a certain amount of mechanical energy. Which types of energy are included in
zloy xaker [14]
I believe it would be B and C because kinetic and potential energy both go under mechanical energy, electrical and thermal energy are its own kind of energy
4 0
2 years ago
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Two 0.40 kg soccer ball collide elastically in a head-on collision. The first ball starts at rest, and the second ball has a spe
yulyashka [42]

Explanation:

Mass of two soccer balls, m_1=m_2=0.4\ kg

Initial speed of first ball, u_1=0

Initial speed of second ball, u_2=3.5\ m/s

After the collision,

Final speed of the second ball, v_2=0

(a) The momentum remains conserved. Using the conservation of momentum to find it as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

v_1 is the final speed of the first ball

0.4\times 0+0.4\times 3.5=0.4v_1+0.4\times 0

0.4\times 3.5=0.4v_1

v_1=3.5\ m/s

(b) Let E_1 is the kinetic energy of the first ball before the collision. It is given by :

E_1=\dfrac{1}{2}mu_1^2

E_1=\dfrac{1}{2}\times 0.4\times 0

It is at rest, so, the kinetic energy of the first ball before the collision is 0.

(c) After the collision, the second ball comes to rest. So, the kinetic energy of the second ball after the collision is 0.

Hence, this is the required solution.

7 0
2 years ago
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POINTS + BRAINLIEST TO CORRECT ANSWER
Elza [17]

Answer:

<h2>5.3 m</h2>

Explanation:

The standard film size for one popular camera was<u> 79 mm square</u>.

The film was <u>116 mm behind the lens</u>.

If you wanted a picture of your<u> 1.8-m-tall friend to fill half the frame</u>,

find:

how far away from you did she need to stand?

solution:

the other person called friend is 1.8 m tall (1,800mm) stood from the other side to fill up half of the frame of 79mm / 2 = 35 mm.

where the film behind the lens is 116mm as given.

so its a ratio and proportion:

<u>1800 mm </u> =  <u>     39.5 mm   </u>

     x                    116 mm

39.5 (x) = 1800 (116)

x =  <u> 208,800</u>

         39.5

x = 5286 mm * <u>      1  m     </u>

                          1000 mm

x = 5.3 m

4 0
2 years ago
A skydiver finds that she speeds up when she holds her arms close to her body. What does this do?
ArbitrLikvidat [17]

D. Reduces the force of air resistance

7 0
2 years ago
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