Answer:
ΔS° = -268.13 J/K
Explanation:
Let's consider the following balanced equation.
3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)
We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:
ΔS° = ∑np.Sp° - ∑nr.Sr°
where,
ni are the moles of reactants and products
Si are the standard molar entropies of reactants and products
ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]
ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]
ΔS° = -268.13 J/K
The location of the valence electron or the outermost electron is expressed in quantum numbers. There are five quantum numbers: prinicipal (n), angular momentum (l), magnetic (ms) and magnetic spin (ms) quantum numbers. This is based on Bohr's atomic model where electrons orbit around the nucleus. These electrons are in the orbitals with specific energy levels. Starting from energy level 1 that is closest to the nucleus, the energy level decreases to 2, 3, 4, 5, 6, and 7. These energy level numbers represent the principal quantum number. Within each orbital also contains subshell. From increasing to decreasing order, these subshells are the s, p, d and f subshells. These subshells represent the angular momentum quantum numer. Specifically, s=0, p=1, d=2 and f=3. Therefore, if the electron is in the orbital 5p, the quantum number would be: 5, 1. Applying these to the choices, the correct pairing would be:
2p: n=2. l=1
3d: n=3, l=2
2s: n=2. l=0
4f: n=4. l=3
1s: n=1, l=0
Answer:
This question appears incomplete
Explanation:
The equation for the formation of iron(III) thiocyanate complex ion is
Fe³⁺ + SCN⁻ ⇄ Fe(SCN)²⁺
Three factors affect the equilibrium of a reaction
- temperature
- pressure (in gases)
- concentration
Since the formation of Fe(SCN)²⁺ is an exothermic reaction (delta H is negative); an increase in temperature will favor the backward reaction and more reactants will be produced. When the temperature is however reduced, the forward reaction will be favored and more products will be produced.
When the concentration of the reactants increases, the forward reaction is favored and hence more Fe(SCN)²⁺ is produced. However, when the concentration of Fe(SCN)²⁺ decreases, the backward reaction is favored and more reactants are produced.
The compounds containing more than one kind of hybridization (sp, sp2, sp3) for carbon is CH3CH = CHCH3.
<u>Explanation</u>:
- Orbital hybridization is the idea of blending nuclear orbitals into new hybrid orbitals reasonable for the matching of electrons to form chemical bonds in the valence bond hypothesis.
Here CH3CH = CHCH3 contains a carbon atom joined to more than 3 hydrogen atoms.
-
In sp – Hybridisation
1 s-orbital and 1 p-orbital are blended to form two sp – hybrid orbitals, having a straight structure. In sp2 – Hybridisation
1 s-orbital and 2 p-orbitals are blended forming three sp2–hybrid orbitals, having a planar triangular structure. In sp3 – Hybridisation 1 s-orbital and 3 p-orbitals are blended forming four sp3–hybrid orbitals having a tetrahedral structure.
Answer : Below are three ways described in brief for improving the quality of indigenous soap.
1) Add virgin coconut oil which serves as a softener and betel leaf extract. It is used to improve the quality of soap as an antimicrobial agent.
2) Add activated charcoal black granules or powder to the soap, it removes maximum dirt from the skin.
3) Adding a filler which will increase the shelf life of usage of the soap will also improve its quality.
