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Citrus2011 [14]
2 years ago
3

A sample of he gas (2.35 mol) occupies 57.9 l at 300.0 k and 1.00 atm. the volume of this sample is _____ l at 423 k and 1.00 at

m.
Chemistry
1 answer:
ruslelena [56]2 years ago
4 0
The  volume  of  the sample  at 423 k  and 1.00 atm  is calculated using  Charles  law  formula   that is V1/T1 =V2/T2 since  the  pressure is  constant

V1=75.9  L
T1=  300 K
V2=?
T2=423 k

by   making the V2 the  subject  of  the formula

V2=T2V1/T1
V2=  57.9 L  x 423 K/300 K=  81.64 L  is the volume of the  sample
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