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aniked [119]
2 years ago
3

Check all correct statements concerning pentyne.

Chemistry
1 answer:
Ipatiy [6.2K]2 years ago
8 0
1. <span>Pentyne is a hydrocarbon. It is classified as an alkyne. The general formula for the alkyne is CnH2n-2. The functional group of pentyne is a triple bond which is made from one </span>σ bond and two π bonds<span>. </span>Since, it has a triple bond, pentyne is an unsaturated hydrocarbon. The formula of pentyne is C5H8 and it only consists of H and C atoms.

2. Alkenes are also hydrocarbons. But they have at least one double bond. The general formula for the alkenes is CnH2n. Since, it has double bond, alkenes are unsaturated hydrocarbons. The hybridization of C which has double bond is sp². Due to the unsaturation it is a reactive hydrocarbon but less stable than alkanes.

Hence, the false statement is "<span>They are more stable than alkanes."

</span>

3. <span>Butene would have 4 carbon atoms and a </span>double bond.

Butene is an alkene. Since the general formula of alkene is CnH2n, formula for the butene is C4H4 because n = 4. It is an unsaturated hydrocarbon due to the presence of the double bond. The double bond is made from one σ bond and one π bond.


<span>4. Alkenes generally undergo addition reactions.</span>

<span>
</span>

Alkenes are unsaturated hydrocarbons which have double bonds. The hybridization of the carbon atom which has the double bond is sp². Hence, that double bond has one σ bond and one π bond. In addition reactions, the π bond breaks down and another atom is connected to the carbon atom by forming a σ bond. By undergoing addition reaction, the hybridization of c atom which has double bond changes from sp² to sp³.


5. If the carbon atom of hydrocarbon is bonded to less than 4 other atoms, the hydrocarbon is considered unsaturated.


Maximum number of bonds that a carbon atom can form is 4. Those bonds can be formed by forming single bonds with four another atoms of by forming one double bond and two single bond with three atoms or by forming one single bond and one triple bond with to another atoms. The single bonds are saturated and double bonds and triple bonds are considered as unsaturated.


6. <span>Unsaturated hydrocarbons </span>have double bond and triple bonds<span> as their functional groups but saturated hydrocarbons have only single bonds. Due to the unsaturation, </span>they will react readily with other elements and compounds. Although the hydrocarbons are unsaturated, they also have isomers. But the stability of the unsaturated hydrocarbons is less than saturated ones.


7. Alkenes have the general formula as CnH2n. Hence C5H10 is an alkene which has 5 carbon atoms. Since, it is an alkene, that hydrocarbon has a double C-C bond. Since it is an unsaturated one, it is highly reactive than alkanes and unstable. It is less inert than alkanes.


8. The general formula of alkenes is CnH2n.


Alkanes have the general formula as CnH2n+2 and for the alkynes, it is CnH2n-2. The general formula of alkenes and alkynes are given when there is only one double bond or triple bond. Due to the presence of double bonds and triple bonds, alkenes and alkynes are less stable and unsaturated.


9. Benzene is a cyclic closed ring and aromatic alkene. The general formula is CnH2n. Benzene has three double bonds. Hence, three C-C have double bonds which share 2 pairs of electrons. Since, those C-C bonds are double bonds, they have π bonds. The all of C atoms in benzene are sp² hybridized. Hence, all C atoms are actually identical. 


10. 

1. H-C≡C-H is a alkyne which has two carbon atoms. Hence, the name of this is  ethyne.

2. Benzene is a cyclic compound which has both saturated and unsaturated characteristics.

3. The general formula of the alkenes is CnH2n.

4. addition is the typical reaction type for the unsaturated hydrocarbons.

5. The general formula of the alkynes is CnH2n-2.

6. series name of hydrocarbons with triple bond is alkyne.

7. The general formula of the alkenes is CnH2n+2.

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Which condition can cause excessive pressure on the high side of a self contained active recovery device
murzikaleks [220]

Answer:

What can cause excessive pressure on the high side of an active self-contained recovery device? A closed recovery tank inlet valve or excessive air or other non condensables in the recovery tank (either A or B) Portable refillable tanks or containers used to ship recovered refrigerants must meet what standard(s)?

Explanation:

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5 0
1 year ago
Calculate the amount of work done against an atmospheric pressure of 1.00 atm when 500.0 g of zinc dissolves in excess acid at 3
ZanzabumX [31]

Answer:

19,26 kJ

Explanation:

The work done when a gas expand with a constant atmospheric pressure is:

W = PΔV

Where P is pressure and ΔV is the change in volume of gas.

Assuming the initial volume is 0, the reaction of 500g of Zn with H⁺ (Zn(s) + 2H⁺(aq) → Zn²⁺(aq) + H₂(g)) produce:

500,0g Zn(s)×\frac{1molZn}{65,38g}×\frac{1molH_{2}(g)}{1molZn} = 7,648 moles of H₂

At 1,00atm and 303,15K (30°C), the volume of these moles of gas is:

V = nRT/P

V = 7,648mol×0,082atmL/molK×303,15K / 1,00atm

V = 190,1L

That means that ΔV is:

190,1L - 0L = <em>190,1L</em>

And the work done is:

W = 1atm×190,1L = 190,1atmL.

In joules:

190,1 atmL×\frac{101,325}{1atmL} = <em>19,26 kJ</em>

I hope it helps!

5 0
2 years ago
One liter of ocean water contains 35.06 g of salt. What volume of ocean water would contain 1.00 kg of salt? Express your answer
sweet [91]

Answer:

28.52 L

Explanation:

First, let's calculate the density of the ocean, which is the mass divided by the volume:

d = m/V

d = 35.06/1

d = 35.06 g/L

So, for a mass of 1.00 kg = 1000.00 g

d = m/V

35.06 = 1000.00/V

V = 1000.00/35.06

V = 28.52 L

How all the data are expressed with two significant figures, the volume must also be expressed with two.

7 0
2 years ago
In a post office, a 3-m long ramp is used to move carts onto a dock that is higher than 1 m. Which describes how the IMA of this
pishuonlain [190]

Answer:

well I think the answer is it depends on the friction

6 0
2 years ago
Pentacarbonyliron(0) (fe(co)5) reacts with phosphorous trifluoride (pf3) and hydrogen, releasing carbon monoxide: fe(co)5+2pf3+h
vladimir1956 [14]

The limiting reactant can be determined by calculating the moles supplied / moles stoich ratio and the lowest is the limiting reactant.

Fe(CO)5 ratio = [6 g / 195.9 g/mol] / 1

Fe(CO)5 ratio = 0.0306

 

PF3 ratio = [4 g / 87.97 g/mol] / 2

PF3 ratio = 0.0227

 

H2 ratio = [4 g / 2 g/mol] / 1

H2 ratio = 2

 

<span>We can see that PF3 has the lowest ratio, so it is the limiting reactant.</span>

6 0
2 years ago
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