Question

Enter the balanced complete ionic equation for k2so4(aq)+cai2(aq)→caso4(s)+ki(aq). express your answer as a chemical equation. identify all of the phases in your answer.

Answer 1

The ionic equation is as below

Ca^2+(aq) + SO4^2-(aq) ---> CaSO4(s)

EXPLANATION

K2SO4(aq) +Cai2(aq) ---> CaSO4(s) + Ki (aq)

ionic equation

= 2K^+(aq) + SO4^2-(aq) + Ca^2+(aq) + 2i^-(aq) --->CaSO4(s) + 2K^+(aq) +2 i^-(aq)

cancel the spectator ions that is 2k^+ and 2i^-

The net ionic equation is therefore

= Ca^2+(aq) + SO4^2-(aq) ----> CaSO4(s)

Answer 2

The balanced complete ionic equation for the reaction is as follows:

$\boxed{2{{\text{K}}^+}\left({aq}\right)+{\text{SO}}_4^{2-}\left( {aq} \right) + {\text{C}}{{\text{a}}^{2 + }}\left( {aq} \right) + 2{{\text{I}}^-}\left( {aq}\right)\to{\text{CaS}}{{\text{O}}_4}\left(s\right)+2{{\text{K}}^+}\left({aq}\right)+2{{\text{I}}^-}\left( {aq}\right)}$

${{\text{K}}^+}$, ${\text{SO}}_4^{2-}$, ${{\text{I}}^-}$, ${\text{C}}{{\text{a}}^{2+}}$ are present in the aqueous phase while ${\text{CaS}}{{\text{O}}_4}$ exists in solid phase.

Further explanation:

Double displacement reaction is defined as the reaction in which ions of two compounds interchange with each other to form the product. A general double displacement reaction between two compounds AX and BY can be written as follows:

${\text{AX}}+{\text{BY}}\to{\text{AY}}+{\text{BX}}$

The three types of equations that are used to represent the chemical reaction are as follows:

1. Molecular equation

2. Complete ionic equation

3. Net ionic equation

The reactants and products remain in undissociated form in the molecular equation. In the case of complete ionic equation, all the ions that are dissociated and present in the reaction mixture are represented while in the case of net ionic equation only the useful ions that participate in the reaction are represented.

The steps to write the complete ionic reaction are as follows:

Step 1: Write the molecular equation for the reaction with the phases in the bracket.

In the reaction, ${{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}$reacts with ${\text{Ca}}{{\text{I}}_2}$to form ${\text{CaS}}{{\text{O}}_{\text{4}}}$and KI. The balanced molecular equation of the reaction is as follows:

${{\text{K}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\left({aq}\right)+{\text{Ca}}{{\text{I}}_2}\left( {aq} \right) \to {\text{CaS}}{{\text{O}}_{\text{4}}}\left(s\right) + 2{\text{KI}}\left({aq}\right)$

Step 2: Dissociate all the compounds with the aqueous phase to write the complete ionic equation. The compounds with solid and liquid phases remain same. The complete ionic equation is as follows:

$2{{\text{K}}^+}\left({aq}\right)+{\text{SO}}_4^{2-}\left({aq}\right)+{\text{C}}{{\text{a}}^{2 + }}\left( {aq}\right)+2{{\text{I}}^-}\left( {aq}\right)\to{\text{CaS}}{{\text{O}}_4}\left( s \right) + 2{{\text{K}}^+}\left({aq}\right)+2{{\text{I}}^-}\left( {aq} \right)$

Therefore the balanced complete ionic equation is as follows:

$2{{\text{K}}^+}\left( {aq}\right)+{\text{SO}}_4^{2-}\left({aq}\right)+{\text{C}}{{\text{a}}^{2+}}\left( {aq}\right)+2{{\text{I}}^-}\left({aq}\right)\to{\text{CaS}}{{\text{O}}_4}\left( s \right)+2{{\text{K}}^+}\left({aq}\right)+2{{\text{I}}^ - }\left( {aq}\right)$

${{\text{K}}^+}$, ${\text{SO}}_4^{2-}$, ${{\text{I}}^-}$, ${\text{C}}{{\text{a}}^{2+}}$ are present in the aqueous phase while ${\text{CaS}}{{\text{O}}_4}$ exists in solid phase.

Learn more:

1. Balanced chemical equation brainly.com/question/1405182.

2. Oxidation and reduction reaction brainly.com/question/2973661.

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: Double displacement reaction, types of equation, molecular equation, complete ionic equation, net ionic equation, K2SO4, CaI2, KI, I-, K+, SO42-, Ca2+, CaSO4, aqueous phase, solid phase.