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2 years ago

What is the solution to the problem expressed to the correct number of significant figures? 2.13 + 1 = ?

Chemistry

1 answer:

ycow [4]2 years ago

4 0

2.13 + 1 = 3

When adding values, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.

2.13

+1

3.13

The “1” has its last significant figure furthest to the left, so you round off the number to the “units" place. That's the last column that the measurements share.

3.13 → 3 (rounded to the "units" place)

∴ 2.13 + 1 = 3

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When balanced, which equation would have the coefficient 3 in front of any of the reactants? Zn + HCl ZnCl2 + H2 H2SO4 + B(OH)3

Gwar [14]

The correct answer is B. H2SO4 + B(OH)3 B2(SO4)3 + H2O

Hope this helps!

6 0

2 years ago

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Write the formulas for the following ionic compounds: (a) copper bromide (containing the Cu+ ion), (b) manganese oxide (containi

ivann1987 [24]

Answer:The formulas of ionic compounds are:

a) $CuBr$

b) $Mn_2O_3$

c) $Hg_2I_2$

d) $Mg_3(PO_4)_2$

Explanation:

Formulas for the an ionic compounds is determine by:

Criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

(a) Copper bromide :Given that it contains $Cu^+$ ion.

$Cu^++Br^-\rightarrow CuBr$

(b) Manganese oxide : Given that it contains $Mn^{3+}$ ion.

$Mn^{3+}+O^{2-}\rightarrow Mn_2O_3$

(c)Mercury iodide :Given that it contains $Hg_2^{2+}$

$Hg_2^{2+}+I^-\rightarrow Hg_2I_2$

(d) Magnesium phosphate :Given that it contains $PO_4^{3-}$

$Mg^{2+}+PO_4^{3-}\rightarrow Mg_3(PO_4)_2$

4 0

2 years ago

The decomposition of AB given here in this balanced equation 2AB (g)⟶ A2 (g) + B2 (g), has rate constants of 8.58 x 10-9 L/mol s

denis-greek [22]

Answer:

3.24 × 10^5 J/mol

Explanation:

The activation energy of this reaction can be calculated using the equation:

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

Where; Ea = the activation energy (J/mol)

R = the ideal gas constant = 8.3145 J/Kmol

T1 and T2 = absolute temperatures (K)

k1 and k2 = the reaction rate constants at respective temperature

First, we need to convert the temperatures in °C to K

T(K) = T(°C) + 273.15

T1 = 325°C + 273.15

T1 = 598.15K

T2 = 407°C + 273.15

T2 = 680.15K

Since, k1= 8.58 x 10-9 L/mol, k2= 2.16 x 10-5 L/mol, R= 8.3145 J/Kmol, we can now find Ea

ln(k2/k1) = Ea/R x (1/T1 - 1/T2)

ln(2.16 x 10-5/8.58 x 10-9) = Ea/8.3145 × (1/598.15 - 1/680.15)

ln(2517.4) = Ea/8.3145 × 2.01 × 10^-4

7.831 = Ea(2.417 × 10^-5)

Ea = 3.24 × 10^5 J/mol

8 0

2 years ago

Chloe wants to lighten the color of her dark hair, which will require the use of both haircolor and hydrogen peroxide. hydrogen

bearhunter [10]

The answer is developer .

Chloe wants to lighten the color of her dark hair, which will require the use of both hair color and hydrogen peroxide.

Hydrogen peroxide (H₂O₂) is an example of a most commonly used developer in hair color.

Hydrogen peroxide lighten hair color, as it can dissolve darker pigment. According to the natural hair color and the length of time a person will leave hydrogen peroxide on hair, hair can turn somewhere on the color spectrum between caramel, orange and yellow.

7 0

2 years ago

Which statement is true of a reversible reaction at equilibrium?

Vedmedyk [2.9K]

Answer:

The concentration of reactants and the concentration of products are constant.

Explanation:

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7 0

2 years ago

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