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mojhsa [17]
2 years ago
15

Use the drop-down menus to identify the types of properties described. Kerosene was commonly used in lamps because it burns easi

ly. The element nickel has a boiling point of 2,913°C. Copper is used to make electrical wire because it is a good conductor. Cesium produces an explosion when it is added to water. Hydrogen is the least dense of all elements.
Physics
2 answers:
Softa [21]2 years ago
9 0

Answer: Kerosene was commonly used in lamps because it burns easily: Chemical property : It undergoes change in chemical composition and produces carbon dioxide and water.

The element nickel has a boiling point of 2,913°C: Physical property: There is no change in chemical composition and only the state changes from liquid to gas.

Copper is used to make electrical wire because it is a good conductor: Physical property: there is involvement of electrons and no change in chemical composition

Cesium produces an explosion when it is added to water: Chemical property: It undergoes change in chemical composition

Hydrogen is the least dense of all elements : Physical property: There is no change in chemical composition and hence a physical property.

Explanation: Chemical property is defined as properties in which arrangement of atoms present in the substance changes and leads to formation of new substance.

Physical property is defined as properties which leads to change in shape, size or state of the substance and does not involve formation of new products.

Norma-Jean [14]2 years ago
3 0

Chemical Property

Physical Property

Physical Property

Chemical Property

Physical Property

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A wave travels through a medium at 251 m/s and has a wavelength of 5.10 cm. What is its frequency? What is its angular frequency
allochka39001 [22]

Explanation:

It is given that,

Speed of a wave, v = 251 m/s

Wavelength of the wave, λ = 5.1 cm = 0.051 m

(1) The frequency of the wave is given by :

\nu=\dfrac{v}{\lambda}

\nu=\dfrac{251\ m/s}{0.051\ m}

\nu=4921.56\ Hz

(2) Angular frequency of the wave is given by :

\omega=2\pi\nu

\omega=2\pi\times 4921.56\ Hz

\omega=30923.07\ rad/s

(3) The period of oscillation is given by T as :

T=\dfrac{1}{\nu}

T=\dfrac{1}{4921.56}

T = 0.000203 seconds

or

T = 0.203 milliseconds

Hence, this is the required solution.

5 0
2 years ago
What is the mass of an object weighing 63 N on Earth?
avanturin [10]
Weight expressed in Newtons is expressed in the equation whereby Weight= the mass of an object * the force of gravity. The force of gravity on earth is a constant 9.8 meters per second squared. Therefore if weight (w) = 63 N and the force of gravity is 63 N then the mass must equal 6.43 kg. Because the equation for weight is w=mg so 63 N (w) = m * 9.8 m/s^2. 
3 0
2 years ago
Daniel is 50.0 meters away from a building. He observes that his line-of-sight to the tip of the building makes an angle of 63.0
frez [133]
Since his line of sight 63 degrees makes with the tip of the building

Tan63° =  height of building / Horizontal distance

tan63° =  Height / 50

50tan63° = Height

Height = 50tan63°

Height ≈ 50*1.9626

Height ≈ 98.13 m

Height of the building is ≈ 98.13 m. Mind you in solving for this height we have neglected the height of Daniel.

The height of building actually should be 98.13 m plus the height of Daniel. Since the 63° was measured from his eye level.
4 0
2 years ago
A small crack occurs at the base of a 15.0-m-high dam. The effective area through which water leaves is 2.30 × 10-3 m2. (a) Igno
vova2212 [387]

Answer

given,                                              

height of the dam = 15 m            

effective area of water = 2.3 x 10⁻³ m²

Using energy conservation              

    m g h = \dfrac{1}{2}mv^2

    v= \sqrt{2gh}                  

    v= \sqrt{2\times 9.8 \times 15}

    v= \sqrt{294}              

           v = 17.15 m/s            

 discharge of water

      Q = A V                            

      Q = 2.3 x 10⁻³ x 17.15    

      Q = 0.039 m³/s

3 0
2 years ago
A roller coaster travels 200 feet horizontally and then rises 135 feet at an angle of 30 degrees above the ground. What is the m
Delvig [45]
Say the initial point is (0,0)

The final point is

x = 200 + 135*cos(30) = 200 + 135*sqrt(3)/2 = 316.91 ft
y = 135*sin(30) = 135/2 = 67.5 ft

Resultant vector = (316.91, 67.5) - (0,0) = 316.91, 67.5) ft
8 0
2 years ago
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