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2 years ago

A draw the structures of the products of the neutralization reaction between methylamine and acetic acid.

Chemistry

2 answers:

BaLLatris [955]2 years ago

7 0

Answer : The neutralization reaction between methylamine and acetic acid are shown below.

Explanation :

Neutralization reaction : It is a type of chemical reaction in which an acid completely neutralizes the base to give a salt and water as a product. It is also know as acid-base reaction.

As we know that, the acetic acid is a strong acid and methylammine is a base. So, they undergoes neutralization reaction. That means, when acetic acid reacts with a methylammine base then it gives acetate ion and methanaminium.

The neutralization reaction between methylamine and acetic acid are shown below.

lyudmila [28]2 years ago

3 0

Acetic acid CH3COOH

Methyl amine CH3NH2

When an acid is reacted with base creating water or solvent and an ionic salt, the reaction is known as Acid-base neutralization reaction.

CH3COOH + CH3NH2 ---(aq )- > CH3COONH3+

CH3COONH3+ -- CH3COO- + NH3+

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Using the following thermochemical equation, determine the amount of heat produced from the combustion of 24.3 g benzene (C6H6).

Anna007 [38]

Answer:

ΔH = -976.5 kJ

Explanation:

For the reaction given, there are 2 moles of benzene (C6H6). The heat of this reaction is -6278 kJ, which means that the combustion of 2 moles of benzene will lose 6278 kJ of heat. It is an exothermic reaction.

The value of ΔH, the enthalpy, is a way of measurement of the heat, and it depends on the quantity of the matter (number of moles).

So, 24.3 g of benzene has :

n = mass/ molar mass

n = 24.3/78.11

n = 0.311 moles

2 moles ------------ -6278 kJ

0.311 moles ----------- x

By a simple direct three rule:

2x = -1953.08

x = -976.5 kJ

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2 years ago

Which family on the periodic table is least likely to enter into chemical reactions? 1 2 17 18

vekshin1

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18 is the answer

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2 years ago

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If the concentration of a saturated solution at 0∘C is 12.5 gCuSO4/100 g soln, what mass of CuSO4⋅5H2O would be obtained? [Hint:

Andrew [12]

Answer:

Mass of CuSO4.H2O obtained: $m_{total}=19.52 g$

Explanation:

The molecular weight of the salt is: $M=159.5 g/mol$

<u>In the solution</u>: 12.5 g of CuSO4

In moles: $n=\frac{12.5 g}{159.5 g/mol}=0.078 mol$

<u>Mass of wate</u>r:

5 moles of water per mol of salt: $m=\frac{5mol}{1mol}*0.078mol*\frac{18g}{mol}=7.02 g$

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Sholpan [36]

Answer:

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