All categories

2 years ago

What would happen if you added more than 5 mL of H2O2 to the5 ml of yeast?

Chemistry

1 answer:

ElenaW [278]2 years ago

7 0

Hydrogen peroxide breaks down into water and oxygen.

2H₂O₂ → 2H₂O + O₂

The yeast present contains an enzyme called catalase which catalyses the reaction.

More the amount of the catalyst added, faster will be the decomposition of the hydrogen peroxide.

Thus if we added more than 5 mL of yeast solution to the 2H₂O₂, the breakdown would occur faster. Thus the bubbles and the accompanying fizz would be much more.

Read more on Brainly.com - brainly.com/question/10670134#readmore

You might be interested in

How do both plants and animals fight pathogens. A.both have a protective outer layer B.both have an antigen-antibody response C.

ira [324]

Both plants and animals fight pathogens is because both have an ant. The answer is B.

Pathogens is a bacterium, virus, or other microorganism that can cause disease.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

3 0

2 years ago

Read 2 more answers

At 4.00 L, an expandable vessel contains 0.864 mol of oxygen gas. How many liters of oxygen gas must be added at constant temper

fgiga [73]

Answer:

We have to add 2.30 L of oxygen gas

Explanation:

Step 1: Data given

Initial volume = 4.00 L

Number of moles oxygen gas= 0.864 moles

Temperature = constant

Number of moles of oxygen gas increased to 1.36 moles

Step 2: Calculate new volume

V1/n1 = V2/n2

⇒V1 = the initial volume of the vessel = 4.00 L

⇒n1 = the initial number of moles oxygen gas = 0.864 moles

⇒V2 = the nex volume of the vessel

⇒n2 = the increased number of moles oxygen gas = 1.36 moles

4.00L / 0.864 moles = V2 / 1.36 moles

V2 = 6.30 L

The new volume is 6.30 L

Step 3: Calculate the amount of oxygen gas we have to add

6.30 - 4.00 = 2.30 L

We have to add 2.30 L of oxygen gas

4 0

2 years ago

According to the quantum-mechanical model for the hydrogen atom, which electron transition produces light with the longer wavele

LekaFEV [45]

Answer:

Explanation:

The main task here is that there are some missing gaps in the above question that needs to be filled with the appropriate answers. So, we are just going to do rewrite the answer below as we indicate the missing gaps by underlining them and making them in bold format.

SO; In the quantum-mechanical model of the hydrogen atom.

As the n level increases. the energy increases and thus levels are closer to each other. Therefore, the transition 3p→2s would have a greater energy difference than the transition from 4p→3p.

$Energy \ and \ wavelength \ are \ inversely \ proportional , \ so \ the \ \mathbf{ 4p\to 3p} \ transition \ would$ $produce \ a \ longer \ wavelength.$

3 0

2 years ago

How many atoms of S are in 98.0 grams of hydrosulfuric acid?

noname [10]

<h2>Answer: $6.022\times 10^{23}$ </h2>

Explanation:

The formula for sulphuric acid is $H_{2}SO_{4}$ .

Molecular mass of sulphuric acid is $2(2)+32+16(4)=98g$

$given weight=98g$

Number of moles of sulphuric acid given is $\frac{\text{given weight}}{molar mass}$ = $\frac{98}{98}=1$

The formula indicates that one mole of $H_{2}SO_{4}$ contains $2$ moles of $H$ atoms, $1$ mole of $S$ atoms, $4$ moles of $O$ atoms.

So,the compound contains $1$ mole of sulphur atoms.

$1$ mole of sulphur has $6.022\times 10^{23}$ atoms

7 0

2 years ago

A 20.6-L sample of "pure" air is collected in Greenland at a temperature of 220.0°C and a pressure of 1.01 atm and is forced int

KATRIN_1 [288]

Answer :

(a) The pressure inside the bottle just after it filled is 19.8 atm.

(b) The pressure inside the bottle as it opened in the 21.0°C is 11.8 atm.

Explanation :

Part (a) :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$

or,

$P_1V_1=P_2V_2$

where,

$P_1$ = initial pressure of gas = 1.01 atm

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = 20.6 L

$V_2$ = final volume of gas = 1.05 L

Now put all the given values in the above equation, we get:

$1.01atm\times 20.6L=P_2\times 1.05L$

$P_2=19.8atm$

Therefore, the pressure inside the bottle just after it filled is 19.8 atm.

Part (b) :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$