Answer:
The solubility of MnS will decrease on addition of KOH solution.
Explanation:
As per the equation given:
On dissolution of MnS in water it gives a basic solution as it gives hydroxide ions.
Now when the we are adding aqueous KOH solution, it will dissociate as:
Thus it will further furnish more hydroxide ion,
This will increase the concentration of hydroxide ions (present of product side), the system will try to decrease its concentration by shifting towards reactant side.
Thus the solubility of MnS will decrease on addition of KOH solution.
0.6137 g of KHP contains 1.086 × 10^21 acidic protons.
Number of moles of KHP = mass of KHP/molar mass of KHP
Molar mass of KHP = 204.22 g/mol
Mass of KHP = 0.6137 g
Number of moles of KHP = 0.6137 g/204.22 g/mol = 0.003 moles of KHP
Now, 1 each molecule of KHP contains 1 acidic proton.
For 0.003 moles of KHP there are; 0.003 × 1 × NA
Where NA is Avogadro's number.
So; 0.003 moles of KHP contains 0.003 × 1 × 6.02 × 10^23
= 1.086 × 10^21 acidic protons.
Learn more: brainly.com/question/16672114
Answer:
Molarity = 0.01 M
Explanation:
Molarity is used to measure the concentration of a solution. It will be same for the whole solution or a small amount of solution if the solution is homogeneous.
So, <u>Molarity of 200 mL of solution = Molarity of 50 mL of solution</u>
given mass of aspirin = 360 mg = 0.36 g
molar mass of aspirin = 180 g
Volume of solution = 200 mL = 0.2 L
Therefore, Molarity = 0.01 M
Answer:
Explanation:
First of all we need to find the amount of atoms per volume (m³). We can do this using the density and the molar mass.
Now, the fraction of vacancies is equal to the N(v)/N ratio.
- N(v) is the number of vacancies
- N is the number of atoms per volume calculated above.
Therefore:
The fraction of vacancies at 600 °C will be:
I hope it helps you!
