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Bad White [126]
2 years ago
9

A 8kg cat is running 4m/s. how much kinetic energy does it have?

Physics
2 answers:
Daniel [21]2 years ago
7 0
The formula for kinetic energy is, { E }_{ k }=\frac { 1 }{ 2 } \cdot m\cdot { v }^{ 2 } 
where m is mass and v is velocity.

Let's plug the given values in the formula.

{ E }_{ k }=\frac { 1 }{ 2 } \cdot m\cdot { v }^{ 2 }\\ \\ { E }_{ k }=\frac { 1 }{ 2 } \cdot 8\cdot { 4 }^{ 2 }\\ \\ { E }_{ k }=\frac { 1 }{ 2 } \cdot 8\cdot 16\\ \\ { E }_{ k }=4\cdot 16\\ \\ { E }_{ k }=64\quad \\ \\

It's kinetic energy is 64 Joules.
olya-2409 [2.1K]2 years ago
6 0

Kinetic energy = (1/2) (mass) (speed)²

Kinetic energy = (1/2) (8 kg) (4 m/s)² =
 
                                  (4 kg) (16 m²/s²) =

                                   64  (kg-m/s²) (m) = 64 newton-m = <em>64 joules</em>


And may I say . . . that is one fat cat !     (about 17.6 pounds)


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Explain how cognitive psychologists combine traditional conditioning models with cognitive processes.
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Behaviorists generally claimed that conditioning occurred without thinking or reasoning ans was simply a result of consequences or reinforcement. Cognitive psychologists demonstrated that thinking and reasoning (cognition) influences the conditioning processes and that many behaviors that are conditioned depend on the type of cognitive reasoning that occurs during conditioning. Therefore, as one is being conditioned to respond to environmental stimuli or is responding to a consequence, they are also pondering and thinking about the process occuring. Cognition is often the reason individuals are not all conditioned in the same manner.
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2 years ago
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Small blocks, each with mass m, are clamped at the ends and at the center of a rod of length L and negligible mass. Compute the
fenix001 [56]

Answer:

Answered

Explanation:

a) Two balls are at a distance of L/2 from the axis of rotation and one block at the center. ( center of rod).

therefore,

I=2\times m\frac{L}{2}^2

I= \frac{1}{2}mL^2

b) two balls at a distance L/4 at the from the axis and 1 ball at a distance 3L/4 from the from the axis.

I= 2\times m\times(L/4)^2 + m(\frac{3L}{4})^2

= \frac{1}{16} mL^2(2+9)= \frac{11}{16}mL^2

5 0
2 years ago
A moving sidewalk 95 m in length carries passengers at a speed of 0.53 m/s. One passenger has a normal walking speed of 1.24 m/s
Archy [21]

Answer:

a) t = 1.8 x 10² s

b) t = 54 s

c) t = 49 s

Explanation:

a) The equation for the position of an object moving in a straight line at constan speed is:

x = x0 + v * t

where

x = position at time t

x0 = initial position

v = velocity

t = time

In this case, the origin of our reference system is at the begining of the sidewalk.

a) To calculate the time the passenger travels on the sidewalk without wlaking, we can use the equation for the position, using as speed the speed of the sidewalk:

x = x0 + v * t

95 m = 0m + 0. 53 m/s * t

t = 95 m/ 0.53 m/s

t = 1.8 x 10² s

b) Now, the speed of the passenger will be her walking speed plus the speed of th sidewalk (0.53 m/s + 1.24 m/s = 1.77 m/s)

t = 95 m/ 1.77 m/s = 54 s

c) In this case, the passenger is located 95 m from the begining of the sidewalk, then, x0 = 95 m and the final position will be x = 0. She walks in an opposite direction to the movement of the sidewalk, towards the origin of the system of reference ( the begining of the sidewalk). Then, her speed will be negative ( v = 0.53 m/s - 2*(1.24 m/s) = -1.95 m/s. Then:

0 m = 95 m -1.95 m/s * t

t = -95 m / -1.95 m/s = 49 s

3 0
2 years ago
A boy throws a 15 kg ball at 4.7 m/s to a 65 kg girl who is stationary and standing on a skateboard. After catching the ball, th
jek_recluse [69]

Answer:

a)v_{f}=0.88m/s

Explanation:

To solve this problem we use the Momentum's conservation Law, before and after the girl catch the ball:

\\ p_{1}=p_{2}\\m_{ball}*v_{o.ball}+m_{girl}*v_{o.girl} = m_{ball}*v_{f.ball} + m_{girl}*v_{f.girl}        (1)

At the beginning the girl is  stationary:

v_{o.girl}=0m/s       (2)

If the girl catch the ball, both have the same speed:

v_{f.girl}=v_{f.ball}=v_{f}       (3)

We replace (2) and (3) in (1):

m_{ball}*v_{o.ball} = (m_{ball}+m_{girl})*v_{f} \\

We can now solve the equation for v_{f}:

v_{f}=\frac{m_{ball}*v_{o.ball}}{(m_{ball}+m_{girl})}=\frac{15*4.7}{15+65}=0.88m/s

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Floor lamps usually have a base with large inertia, while the long body and top have much less inertia. Part A If you want to sh
Novay_Z [31]

Answer:

When a an object is been rotated its resistance capacity to that rotational force is know as rotational inertia  and this mathematically given as

          I = mr^2

   Where m is the mass

                r is the rotation radius

For the spinning of the lamp as a baton to work the location of the center of mass of the floor lamp needs to be located

This is more likely to be located closer to base of the lamp as compared to the top, so success of spinning a floor lamp like a baton is highly likely if the lamp is grabbed closer to the base because that is where the position of its center of mass is likely to be.

Explanation:

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2 years ago
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