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2 years ago

What word chemical equation describes Cavendish’s experiment with zinc?

1 answer:

7 0

The chemical reaction of Cavendish involving zinc would be a reaction between hydrochloric acid and zinc yielding zinc chloride and hydrogen gas.

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An object is 6.0 cm in front of a converging lens with a focal length of 10 cm.Use ray tracing to determine the location of the

Masja [62]

As we know that

$\frac{1}{d_i} + \frac{1}{d_0} = \frac{1}{f}$

here we know that

$d_0 = 6 cm$

$f = 10 cm$

now from above equation we have

$\frac{1}{d_i} + \frac{1}{6} = \frac{1}{10}$

$d_i = -15 cm$

so image will form on left side of lens at a distance of 15 cm

This image will be magnified and virtual image

Ray diagram is attached below here

8 0

2 years ago

While looking at bromine (Br) on the periodic table, a student needs to find another element with very similar chemical properti

Ede4ka [16]

Answer: There are many possible elements, and they are all in the same vertical column as bromine.

Explanation:

In a periodic table, the elements are arranged according to the atomic number. The elements arranged in the same vertical column (known as groups) have same valence configuration and therefore have same chemical properties. Hence, there would be more possible elements having same chemical properties in the same vertical column (group) as Bromine.

7 0

2 years ago

Read 2 more answers

Considerable scientific work is currently under way to determine whether weak oscillating magnetic fields such as those found ne

slega [8]

Answer:

$\epsilon = 2.96 \times 10^{-11} \ V$

Explanation:

given,

magnetic field strength = 1.40 ✕ 10⁻³ T

frequency of oscillation = 60 Hz

diameter of RBC = 7.5 μm

EMF = ?

$\epsilon = NBA\omega$

$\epsilon = NB(\pi\ r^2)\ (2\pi f)$

$\epsilon = NB(\pi\ (\dfrac{d}{2})^2)\ (2\pi f)$

$\epsilon = (1)\ 1.4 \times 10^{-3}(\pi\ (\dfrac{7.5 \times 10^{-6}}{2})^2)\ (2\pi\times 60)$

$\epsilon = 2.96 \times 10^{-11} \ V$

maximum emf that can generate around the perimeter of the cell $\epsilon = 2.96 \times 10^{-11} \ V$

5 0

2 years ago

The expressions for e/m and the relative error of e/m due to all of the parameters measured:

bija089 [108]

Answer:

Term 1 = (0.616 × 10⁻⁵)

Term 2 = (7.24 × 10⁻⁵)

Term 3 = (174 × 10⁻⁵)

Term 4 = (317 × 10⁻⁵)

(σ ₑ/ₘ) / (e/m) = (499 × 10⁻⁵) to the appropriate significant figures.

Explanation:

(σ ₑ/ₘ) / (e/m) = (σᵥ /V)² + (2 σᵢ/ɪ)² + (2 σʀ /R)² + (2 σᵣ /r)²

mean measurements

Voltage, V = (403 ± 1) V,

σᵥ = 1 V, V = 403 V

Current, I = (2.35 ± 0.01) A

σᵢ = 0.01 A, I = 2.35 A

Coils radius, R = (14.4 ± 0.3) cm

σʀ = 0.3 cm, R = 14.4 cm

Curvature of the electron trajectory, r = (7.1 ± 0.2) cm.

σᵣ = 0.2 cm, r = 7.1 cm

Term 1 = (σᵥ /V)² = (1/403)² = 0.0000061573 = (0.616 × 10⁻⁵)

Term 2 = (2 σᵢ/ɪ)² = (2×0.01/2.35)² = 0.000072431 = (7.24 × 10⁻⁵)

Term 3 = (2 σʀ /R)² = (2×0.3/14.4)² = 0.0017361111 = (174 × 10⁻⁵)

Term 4 = (2 σᵣ /r)² = (2×0.2/7.1)² = 0.0031739734 = (317 × 10⁻⁵)

The relative value of the e/m ratio is a sum of all the calculated terms.

(σ ₑ/ₘ) / (e/m)

= (0.616 + 7.24 + 174 + 317) × 10⁻⁵

= (498.856 × 10⁻⁵)

= (499 × 10⁻⁵) to the appropriate significant figures.

Hope this Helps!!!

6 0

2 years ago

Serena is a research student who has conducted an experiment on the discoloration of marble. Read about Serena’s experiment. The

sergij07 [2.7K]

The two flaws in her experiment’s design are

<span>- She introduced at least one confounding variable.</span> <span>- She tried to test multiple hypotheses at a time</span>

In the above mentioned experiment she had to have four samples to prove four hypotheses, each one separately and not to mix two hypotheses in an alone sample, that what it brings as consequence is the confusion.

3 0

2 years ago