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vodka [1.7K]
2 years ago
9

How many miles are in 37km

Chemistry
2 answers:
DanielleElmas [232]2 years ago
7 0

There are 22.99073411 miles in 37 kilometers.

You would use the formula (Miles = Kilometers * 0.621371192) to get your answer.

Other calculations:

37 kilometer(s) = 40463.69 yards

37 kilometer(s) = 121391.08 feet or foot

37 kilometer(s) = 1456692.91 inches

Hope this helps! :)

Ne4ueva [31]2 years ago
4 0

There are 22.9907 miles in 37 km

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Given that there is 48 liters of gasoline to be burned and that 45 kJ of energy is released per gram of gasoline burned, the amount of energy that the gasoline fuel produces can then be calculated, First, we convert 48 liters of gasoline to units of mass (grams) in order to use the given conversion of 45 kJ per gram of gasoline. To do this, we use the density of gasoline which is 0.77 g/mL. The following expression is then used:

48 L gasoline x 1000 mL/L x 0.77 g/mL x 45 kJ/g gasoline = 1663200 kJ

<span>The amount of energy produced by burning 48 L of gasoline was then determined to be 1663200 kJ. </span>    
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2 years ago
What types of compounds are CaCl2, Cu, C2H6, respectively.
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Ionic, metal, organic

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In this case, we have to analyze each compound:

-) CaCl_2

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CaCl_2~->~Ca^+^2~+~2Cl^-

The cation would be Ca^+^2 and the anion is Cl^-. So, we will have an <u>ionic compound.</u>

-) Cu

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-) C_2H_6

In this molecule, we have single bonds between carbon and hydrogen. The electronegativity difference between C and H are not high enough to produce ions. So, with this in mind, we will have covalent bonds. This is the main characteristic of <u>organic compounds. </u> (See figure 1)

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2 years ago
Microwave ovens are able to cook food because they increase the_______ of water molecules in the food.
Whitepunk [10]

potential energy with the heat given to the food

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2 years ago
A 6.0M solution HCl is diluted to 1.0M How many milliliters of the 6.0M solution would be used to prepare 100.o mL of the dilute
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2 years ago
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A 25.0 g sample of an alloy was heated to 100.0 oC and dropped into a beaker containing 90 grams of water at 25.32 oC. The tempe
elena55 [62]

Answer:

The specific heat of the alloy C_{a} = 0.37 \frac{KJ}{Kg K}

Explanation:

Mass of an alloy m_{a} = 25 gm

Initial temperature T_{a} = 100°c = 373 K

Mass of water m_{w} = 90 gm

Initial temperature of water T_{w} = 25.32 °c = 298.32 K

Final temperature T_{f} = 27.18 °c = 300.18 K

From energy balance equation

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C_{a} = 0.37 \frac{KJ}{Kg K}

This is the specific heat of the alloy.

4 0
2 years ago
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