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Novay_Z [31]
2 years ago
9

To dazzle his students, Mr. Turner collected volumes of ammonia gas and carbon dioxide gas. As the two colorless gases were comb

ined in a closed two-liter bottle with a small amount of ammonium hydroxide, the chemistry students watched in amazement at the growth of white crystals inside the bottle. What happened inside the bottle as the gases were mixed?
Chemistry
1 answer:
Yuliya22 [10]2 years ago
8 0

Answer: a chemical change

Explanation:

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What is the molarity of a HNO3 solution prepared by adding 290.7 mL of water to 350.0 mL of 12.3 M HNO3?
Lisa [10]

Answer:

6.72M of HNO3

Explanation:

In the problem you are diluting the original HNO3 solution by the addition of some water. The final volume is:

290.7mL + 350.0mL = 640.7mL

And you are diluting the solution:

640.7mL / 350.0mL = 1.8306 times

As the original concentration was 12.3M, the final concentration will be:

12.3M / 1.8306 =

<h3>6.72M of HNO3</h3>
5 0
2 years ago
Explain how interactions between Earth’s spheres keep water cycling between them
Elenna [48]
There are several process in the nature, which keeps water cycling between them. By Precipitation, Earth's sphere gets water which we use in several ways, and by evaporation & sublimation, it goes back to upper spheres of the Earth's atmosphere and cycle happens again & again.

Hope this helps!
3 0
2 years ago
A rigid, 28-L steam cooker is arranged with a pressure relief valve set to release vapor and maintain the pressure once the pres
MaRussiya [10]

Answer:

\Delta S_{source}>-1.204\frac{kJ}{K}

Explanation:

Hello!

In this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy:

s_1=s_{f,175kPa}+q*s_{fg,175kPa}\\\\s_1=1.4850\frac{kJ}{kg*K} +0.1*5.6865\frac{kJ}{kg*K}=2.0537\frac{kJ}{kg*K}

Now the entropy at the final state given the new 40-% quality:

s_2=s_{f,150kPa}+q*s_{fg,150kPa}\\\\s_2=1.4337\frac{kJ}{kg*K} +0.4*5.7894\frac{kJ}{kg*K}=3.7495\frac{kJ}{kg*K}

Next step is to compute the mass of steam given the specific volume of steam at 175 kPa and the 10% quality:

m_1=\frac{0.028m^3}{(0.001057+0.1*1.002643)\frac{m^3}{kg} } =0.274kg\\\\m_2=\frac{0.028m^3}{(0.001053+0.4*1.158347)\frac{m^3}{kg} } =0.0603kg

Then, we can write the entropy balance:

\Delta S_{source}+\frac{Q}{T_1} -\frac{Q}{T_2} +s_2m_2-s_1m_1-s_{fg}(m_2-m_1)>0

Whereas sfg stands for the entropy of the leaving steam to hold the pressure at 150 kPa and must be greater than 0; thus we plug in:

Which is such minimum entropy change of the heat-supplying source.

Best regards!

3 0
2 years ago
The specific heat of water is 4.18 J/g•°C. How much heat does 225.0 g of water release when it cools from 85.5°C to 50.0°C? Ente
Sergio [31]
The answer is 33400J
4 0
2 years ago
Read 2 more answers
What elements are in NaC2HO4 and how many atoms are in each element​
JulijaS [17]

Answer:

Each molecule contains one atom of A and one atom of B. The reaction does not use all of the atoms to form compounds.

                 A + B ⟶ Product

Particles: 6      8              6

If six A atoms form six product molecules, each molecule can contain only one A atom.

The formula of the product is ABₙ.

If n = 1, we need six atoms of B.

If n = 2, we need 12 atoms of B. However, we have only eight atoms of B, so the formula of the product must be AB.

Thus, 6A + 6B ⟶ 6AB, with two B atoms left over.

Explanation:

Credit goes to @znk

Hope it helps you :))

7 0
2 years ago
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