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inn [45]
2 years ago
3

In some fireworks there is a reaction between powdered aluminium and powdered barium nitrate in which heat is evolved and an unre

active gas is produced.
What is the equation for this reaction?

A. 2Al + Ba(NO3)2 -> Al2O3 + BaO + 2NO
B. 4Al + 4Ba(NO3)2 -> 2Al2O3 + 4 Ba(NO2)2 + O2
C. 10Al + 3 Ba(NO3)2 -> 5Al2O3 + 3BaO + 3N2
D. 10Al + 18Ba(NO3)2 -> 10Al(NO3)3 +18BaO +3N2
Chemistry
2 answers:
Dmitriy789 [7]2 years ago
7 0
I think the correct answer from the choices listed above is option A. The correct equation would be:

<span> 2Al + 3Ba(NO3)2 -> Al2O3 + 3BaO + 6NO2
</span>
The products would be aluminum nitrate, barium oxide and nitrogen dioxide.
wariber [46]2 years ago
7 0

<u>Answer:</u> The correct answer is Option 3.

<u>Explanation:</u>

When aluminium in solid state reacts with powdered barium nitrate, it results in the formation of number of products.

The chemical reaction between aluminium and barium nitrate follows the equation:

10Al+3Ba(NO_3)_2\rightarrow 5Al_2O_3+3BaO+3N_2

By Stoichiometry of the reaction:

10 moles of aluminium reacts with 3 moles of barium nitrate to produce 5 moles of aluminium oxide, 3 moles of barium oxide and 3 moles of nitrogen gas.

Nitrogen gas evolved is the unreactive gas.

Hence, the correct answer is Option 3.

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How many grams of caf2 would be needed to produce 8.41×10-1 moles of f2?
geniusboy [140]
Answer: 65.7 grams

Explanation:

1) ratio

Since 1 mole of CaF2 contains 1 mol of F2, the ratio is:

1 mol CaF2 : 1 mol F2

2) So, to produce 8.41 * 10^ -1` mol of F2 you need the same number of moles of CaF2.

3) use the formula:

mass in grams = molar mass * number of moles

molar mass of CaF2 = 40.1 g/mol + 2 * 19.0 g/mol = 78.1 g/mol

mass in grams = 78.1 g/mol * 8.41 * 10^ -1 mol = 65.7 grams
5 0
2 years ago
Analyze and solve this partially completed galvanic cell puzzle. There are 4 electrodes each identified by a letter of the alpha
klasskru [66]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is  E_{cell}__{AC}} = 0.94

Explanation:

  From the question we are told that

          the cell voltage for AD is  E_{cell}__{AD}} = 1.56V

From the data give we can see that

               E_{cell}__{AD}} - E_{cell}__{BD}} = E_{cell}__{AB}}

i.e           1.56 - 1.53 = 0.03

   In the same way we can say that

              E_{cell}__{AD}}-E_{cell}__{CD}} = E_{cell}__{AC}}

=>        E_{cell}__{AC}}=1.56- 0.62

                       E_{cell}__{AC}} = 0.94

       

             

5 0
2 years ago
The mechanism for the reaction described by 2N2O5(g) ---&gt; 4NO2(g) + O2(g) is suggested to be (1) N2O5(g) (k1)---&gt;(K-1) NO2
aliina [53]
Go add me on Snapchat christian3cruz
5 0
2 years ago
Some instant cold packs contain ammonium nitrate and a separate pouch of water. When the pack is activated by squeezing to break
lubasha [3.4K]

Answer:

T_f=-7.81^0C

Explanation:

Hello,

a) In this case, since the heat associated with the dissolution of ammonium nitrate is positive, such reaction is endothermic as it absorbs heat.

b) Now, for computing the temperature once the dissolution is done, we apply (considering that it is a cooling process):

T_f=T_0-\frac{\Delta H}{mCp}

Nonetheless, we should first compute the moles of the mixture as:

n_{mix}=135.0gH_2O*\frac{1molH_2O}{18gH_2O}+50.0gNH_4NO_3*\frac{1molNH_4NO_3}{80gNH_4NO_3}=8.125mol

Thus, the total absorbed heat is:

\Delta H=25.4kJ/mol*8.125mol=206.375kJ

Now, the temperature is:

T_f=25.0^0C-\frac{25.4kJ}{(135.0+50.0)g*4.184x10^{-3}kJ/g^0C} \\\\T_f=-7.81^0C

Best regards.

3 0
2 years ago
A 3.50 g sample of rice is burned in a bomb calorimeter containing 1680 g of water. The temperature of the water increases from
alex41 [277]

Answer:

3.58 x 10^4 J

Explanation:

5 0
2 years ago
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